Answer:−3+3=−4
2+3−=15
4−3−=19
2 3
Step 1: Pair the equations to eliminate y because the y terms are already additive inverses
1
−3+3=−4
2+3−=15
2
2+3−=15
4−3−=19
2 3 4
3 =11
5
6 −2=34
Step 2: Write the two new equations
as a system
Step 3: Substitute the value for x and z
into one of the original equations
3 =11
3 5 +2=11
4
5−3+3 −2 =−4
15+2=11
5
6 −2=34
5−3−6=−4
−3−1=−4
9x
2=−4
=−2
= 45
x = 5
−3=−3
=1
The solution (5, 1, -2)
Step-by-step explanation:
One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.
In this case, the legs are 3√2 and the hypotenuse is h.
Using the formula:
(3√2)² + (3√2)² = h²
18 + 18 = h²
h = 6
The other way to do this is with trigonometric angles.
Remember cosine is adjacent over hypotenuse.
cos(45°) = (3√2) / h
h = (3√2) / cos(45°)
h = 6
Answer: b. 3x + 2
Step-by-step explanation:
2l + 2w = p
2l + 2(2x - 1) = 10x + 2
2l + 4x - 2 = 10x + 2
2l = 6x + 4
l = 3x + 2
To write an equation you need a slop and y intercept. To find the slop use the formula y2-y1 /x2-x1. and for the y intercept use the formula y=mx+b
