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lesya692 [45]
4 years ago
7

Imagine a 10kg block moving with a velocity of 20m/s to the left.

Physics
1 answer:
lara31 [8.8K]4 years ago
3 0
Kinetic energy , KE= [1/2]m*v^2

m = 10 kg
v=20m/s

KE = [1/][(10kg)(20m/s)^2 = [1/2](10kg)(400m^2/s^2) = 2000 joule

Answer: 2000 joule
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Jerome does not pay his balances off his credit cards each month. He often has to pay interest and finance charges. What is Jero
slega [8]

Jerome is referred to a debtor as he doesn't pay his balances off his credit cards each month.

<h3>Who is a Debtor?</h3>

This is defined as an individual who owes money while on the other hand a deadbeat is a person who pays his balances off his credit cards each month without having to pay interests.

Since jerome failed to pay the balances on the credit card then he is called a debtor.

Read more about Debtor here brainly.com/question/25919625

4 0
2 years ago
HELP...<br> 3.00 amu = _____ Mev.<br><br> 3.22 x 10-3<br> 2.79 x 103<br> 3.10 x 102
DanielleElmas [232]
The correct answer is:
2.79 \cdot 10^3 MeV
Let's see why.

1 amu corresponds to the mass of the proton, which is:
m_p = 1.66 \cdot 10^{-27} kg
if we convert this into energy, using Einstein equivalence between mass and energy, we find:
E=mc^2 = (1.66 \cdot 10^{-27} kg)(3\cdot 10^8 m/s)^2 = 1.49 \cdot 10^{-10} J
Now we can convert it into electronvolts:
E= \frac{1.49 \cdot 10^{-10}kg}{1.6 \cdot 10^{-19} J/eV} =9.34 \cdot 10^9 eV = 934 MeV

So, 1 amu = 934 MeV. Therefore, 3 amu corresponds to 3 times this value:
3 amu = 3 \cdot 934 MeV  \sim 2790 MeV = 2.79 \cdot 10^3 MeV
5 0
4 years ago
Read 2 more answers
The higher the objects " ? ", the more kinetic energy
natita [175]

Answer:

yes

Explanation:

can i get brainlest pls

7 0
3 years ago
Read 2 more answers
An electron and a positron are located 17 m away from each other and held fixed by some mechanism. The positron has the same mas
mariarad [96]

Answer:

Velocity will be 13.9 m/s when they are 1.3 m away from each other.

Explanation:

Detailed steps are attached below.

6 0
3 years ago
I traveled 6.00 km to school in 0.250 hours . What was my average speed
SOVA2 [1]

Answer: 6.67 m/s

Explanation:

Recall that average speed is the total distance covered by a moving body divided by the total time taken. The SI unit is metres per second.

i.e Average speed = distance/time taken

Given that:

Distance covered = 6.00 km

Convert kilometers to meters

If 1 km = 1000 m

6.00 km = (6.00 x 1000) = 6000m

Time taken to school = 0.250 hours

Convert time in hours to seconds

If 1 hour = 60 minutes & 1 minute = 60 seconds

Then, 0.250 hours = (0.250 x 60 x 60)

= 900 seconds

Average speed = ?

Average speed = 6000m/900s

= 6.67 m/s

Thus, your average speed to school is 6.67 m/s

5 0
3 years ago
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