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3 years ago

Write the quadratic equation y=x^2-6+7

Mathematics

1 answer:

sveticcg [70]3 years ago

8 0

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A rectangular field is twelve times as long as it is wide. If the perimeter of the field is 1690 feet, what are the dimensions o

lawyer [7]

Answer:

The width of the field is 65 feet.

The length of the field is 780 feet.

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3 years ago

Sam see you when you divide your answer is always smaller than what you start with

Neko [114]

Answer:

I disagree with Sam

Step-by-step explanation:

Disagree, it is not always correct

Consider dividing 5 by 0.5, you get 10 which is greater than what you started with

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2 years ago

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3 years ago

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State the extremes of the proportion below. 4/7=12/x

yKpoI14uk [10]

$\frac{4}{7} = \frac{12}{x} \\ \\ 1. \: \frac{4}{7}x = 12 \\ \\ 2. \: \frac{4x}{7} = 12 \\ \\ 3. \: 4x = 12 \times 7 \\ \\ 4. \: 4x = 84 \\ \\ 5. \: x = \frac{84}{4} \\ \\ 6. \: x = 21$

7 0

3 years ago

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What is the simplified form of the following expression 7(^3√2x)-3(^3√16x)-3(^3√8x)

svlad2 [7]

Answer:

The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

Step-by-step explanation:

Given : Expression $7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

To Simplified : The expression

Solution :

Step 1 - Write the expression

$7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}$

Step 2- Simplify the roots and re-write as

$16=2^3\times2$ and $8=2^3$

$7\sqrt[3]{2x}-3\times2\sqrt[3]{2x}-3\times2\sqrt[3]{x}$

Step 3- Solve the multiplication

$7\sqrt[3]{2x}-6\sqrt[3]{2x}-6\sqrt[3]{x}$

Step 4- Taking $\sqrt[3]{2x}$ common from first two terms

$\sqrt[3]{2x}(7-6)-6\sqrt[3]{x}$

$\sqrt[3]{2x}-6\sqrt[3]{x}$

Therefore, The simplified form of the expression is $\sqrt[3]{2x}-6\sqrt[3]{x}$

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3 years ago

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