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g100num [7]
3 years ago
12

A square has four sides each measuring 28 inches. The square is dilated by a scale factor of 1/4. What is the perimeter of the r

esulting image?
А
112 inches
B
56 inches
С
28 inches
D
14 inches
Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

Be a good fit for me as well as the first suspect in your area of work experience and experience with your company and my company is a great company and I am very interested

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Justin sold 300 liter of soda at a baseball game.how much is this in milliliters?
qaws [65]
If Justin sold 300 liters of soda, then he would have sold 300000 milliliters of soda. 1 liter= 1000 milliliters
5 0
4 years ago
Read 2 more answers
Name the values of the 4s in the number 3,441.
Mnenie [13.5K]

Answer:

the first 4's value in ''441" is 400 ( its in the hundreds place ) and the the second 4's value in ''441'' is 40 (its in the tens place)

Step-by-step explanation:

3 0
3 years ago
Find the slope and y-intercept of the line. ​
sergey [27]

slope-intercept formula: y = mx + b

m = slope

b = y-intercept

your equation: y = 4/3x - 3

m = 4/3

b = -3

so, the answer would be the last option.

hope this helps, have a great day/night :)

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3 years ago
Bài4 mình không biết làm mọi người help mee
aivan3 [116]
Sorry I can’t read that hand writing if I could just write it on brainly
8 0
3 years ago
The average value of a function f over the interval [−1,2] is −4, and the average value of f over the interval [2,7] is 8. What
Anna71 [15]

The average value of a continuous function f(x) over an interval [a, b] is

\displaystyle f_{\mathrm{ave}[a,b]} = \frac1{b-a}\int_a^b f(x)\,dx

We're given that

\displaystyle f_{\rm ave[-1,2]} = \frac13 \int_{-1}^2 f(x) \, dx = -4

\displaystyle f_{\rm ave[2,7]} = \frac15 \int_2^7 f(x) \, dx = 8

and we want to determine

\displaystyle f_{\rm ave[-1,7]} = \frac18 \int_{-1}^7 f(x) \, dx

By the additive property of definite integration, we have

\displaystyle \int_{-1}^7 f(x) \, dx = \int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx

so it follows that

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(\int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx\right)

\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(3\times(-4) + 5\times8\right)

\displaystyle f_{\rm ave[-1,7]} = \boxed{\frac72}

7 0
3 years ago
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