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madreJ [45]
3 years ago
8

Closeness of a measurement to the actual value of the dimension being measured. For example, a measurement of 1.99999 cm for an

object that is 2 cm wide has a high level of accuracy? a.precision b.conversion factor c.quantify d.accuracy?
a. precision
b. conversion factor
c. quantify
d. accuracy
Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

d. accuracy

Step-by-step explanation:

In measurements, accuracy is a term that is used to describe the closeness of a measured value to the actual or true value. While precision describes how close different measured values are to each other.

Thus when a measured value is accurate, it implies that the value is very close or almost equal to the true value. The correct answer to the question is  is option D.

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The quotient of a number and -5 increased by 7 is a minimum 1
bagirrra123 [75]

Answer:

Step-by-step explanation:

(x / -5) + 7 ≥ 1

4 0
3 years ago
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Help me please, thank you :) ​
AfilCa [17]

<u>Answer:</u>

<em>101.6 feet</em>

<u>Step-by-step explanation:</u>

<em>First compute the perimeter of the first two windows: (3.4+5.2)*2=17.2</em>

<em>The perimeter of the four other windows: (3.6+4.8)*2=16.8</em>

<em>The total number of feet needed for the first two windows:</em>

<em>17.2*2 = 34.4 feet</em>

<em>The total number of feet needed for the four windows:</em>

<em>16.8*4 = 67.2 feet</em>

<em />

<em>The total number of feet needed is then: 34.4 + 67.2 = 101.6 feet.</em>

6 0
3 years ago
Shane is using pieces of square paper to cover a cube shaped gift with sides that are 9 inches long to find out the area of the
nordsb [41]

Answer:

The area of the cube is 486 inches^2

Step-by-step explanation:

In this question, we are tasked with calculating the area of cube with side 9 inch.

Mathematically, the area can be calculated using the formula A = 6s^2

Now, what we need to do is to substitute 9 inches for s

Thus, A = 6 * 9^2

A = 6 * 81

A = 486 inches^2

3 0
3 years ago
FIND the GCF <br><img src="https://tex.z-dn.net/?f=y%28%20x%5E%7B2%7D%20%2B2%29%2B3%28%20x%5E%7B2%7D%20%2B2%29" id="TexFormula1
Tju [1.3M]
GCF(y(x² + 2) + 3(x² + 2)) = x² + 2

(y - 3)(x² + 2)
y(x² + 2) - 3(x² + 2)
y(x²) + y(2) - 3(x²) - 3(2)
x²y + 2y - 3x² - 6
x²y - 3x² + 2y - 6
(y - 3)x² + 2y - 6
5 0
3 years ago
Which set of four test scores would have the biggest difference between the mean and the median? A. 32, 85, 89, 91, 92, 92 B. 72
postnew [5]

Answer:

A. 32, 85, 89, 91, 92, 92

Step-by-step explanation:

A. 32, 85, 89, 91, 92, 92

Mean

\bar{x}=\dfrac{32+85+89+91+92+92}{6}\\\Rightarrow \bar{x}=80.167

Since the number of scores is 6 which is an even number the median will be of the form \dfrac{x_{n/2}+x_{(n/2)+1}}{2}

Median

\dfrac{89+91}{2}=90

Difference of mean and median = |80.167-90|=9.83

B. 72, 78, 79, 80, 82, 82

Mean

\bar{x}=\dfrac{72+78+79+80+82+82}{6}\\\Rightarrow \bar{x}=78.83

Median

\dfrac{79+80}{2}=79.5

Difference of mean and median = |78.83-79.5|=0.67

C. 65, 70, 75, 80, 85, 90

Mean

\bar{x}=\dfrac{65+70+75+80+85+90}{6}\\\Rightarrow \bar{x}=77.5

Median

\dfrac{75+80}{2}=77.5

Difference of mean and median = |77.5-77.5|=0

D. 30, 34, 39, 41, 48, 50

\bar{x}=\dfrac{30+34+39+41+48+50}{6}\\\Rightarrow \bar{x}=40.33

Median

\dfrac{39+41}{2}=40

Difference of mean and median = |40.33-40|=0.33

So, A has the maximum difference of 9.83 between the mean and the median.

6 0
3 years ago
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