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Anastaziya [24]
3 years ago
9

in  mrs. middleton's math class, there are 7 more boys than girls. if there are  29 total students in the cla

ss, how many boys are there?
Mathematics
2 answers:
Vadim26 [7]3 years ago
7 0
17 boys and 12 girls
Bas_tet [7]3 years ago
4 0
You have 17 guys and 12 girls
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(2³)² solve this problem
max2010maxim [7]

Answer:

(2^3)^2 = 64

Step-by-step explanation:

Option 1:

Using the following rule:

(a^n)^m = a^{nm}

Put in our expression,

a = 2

n = 3

m = 2

(a^n)^m = a^{nm}

(2^3)^2 = 2^{3*2}=2^6=64

Option 2:

Using the following rule:

a^n * a^m = a^{n+m}

Since our expression is the same as multiplying 2³ with itself, we can write it as a multiplication.

(2^3)^2 = 2^3 * 2^3

If we compare this with a^n * a^m, we can see that

a = 2

n = 3

m = 3 (in this case, n and m are equal)

a^n*a^m = a^{n+m}

2^3*2^3 = 2^{3+3} = 2^6 = 64

Answer: (2^3)^2 = 64

7 0
3 years ago
while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D
alexandr1967 [171]

\bold{\huge{\orange{\underline{Solution}}}}

\bold{\underline{ Given :- }}

  • <u>While </u><u>shopping </u><u>for </u><u>clothes </u><u>Tracey </u><u>spent </u><u>3</u><u>8</u><u>$</u><u> </u><u>less </u><u>than </u><u>3</u><u> </u><u>times </u><u>of </u><u>what </u><u>Daniel </u><u>spent </u>

\bold{\underline{ To\: Find :- }}

  • <u>We </u><u>have </u><u>to </u><u>determine </u><u>the </u><u>total </u><u>cost </u><u>spent </u><u>by </u><u>daniel</u>

\bold{\underline{ Let's \: Begin :- }}

Cost spent by Tracey for her clothes = 38$

Let assume the spending by Daniel is x

\bold{\underline{Therefore ,}}

\sf{ x / 3 = 38 }

\sf{ x  = 38 × 3 }

\sf{ x = 114 dollar }

\sf{\red{ Hence,\: Daniel\: spent\: 114 \: dollars\: on \: His\: clothes }}

7 0
2 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
How many tenths are in 13.58
Naily [24]
Tenths is after the decimal so the tenths is 5.
3 0
3 years ago
There is a 72% chance that you will get an exam next week. What is the probability that you will NOT get an exam next week?
Yuliya22 [10]
100 minus 72 equals to 28. 28% of NOT getting an exam next week
5 0
2 years ago
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