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gulaghasi [49]
3 years ago
9

Write the equation y = 4/5x - 7/10 in standard form. (Standard form is Ax+By = C, where A is positive, and A, B, and C are integ

ers with greatest common divisor 1.)
Mathematics
1 answer:
nekit [7.7K]3 years ago
3 0

The equation y = \frac{4}{5} x - \frac{7}{10} in standard form is 8x - 10y = 7

Step-by-step explanation:

The standard form of a linear function is Ax + By = C, where

  • A is positive
  • A, B, and C are integers with greatest common divisor 1

∵ The equation is y = \frac{4}{5} x - \frac{7}{10}

- At first multiply the terms of the equations by the least common

  multiple of 5 and 10 to cancel the denominators of the fractions

∵ The least common multiple of 5 and 10 is 10

- Multiply all the terms of the equations by 10

∵ 10(y) = 10( \frac{4}{5} ) x - 10( \frac{7}{10} )

∴ 10y = 8x - 7

- Subtract 8x from both sides

∴ 10y - 8x = -7

- Multiply each term by -1 to make the coefficient of x positive

∴ -10y + 8x = 7

- Start with x

∴ 8x - 10y = 7 ⇒ (the greatest common divisor of 8 , 10 , 7 is 1)

The equation y = \frac{4}{5} x - \frac{7}{10} in standard form is 8x - 10y = 7

Learn more:

You can learn more about the linear equations in brainly.com/question/9801816

#LearnwithBrainly

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Answer:

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

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Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of $50 and a standard deviation of $15.

This means that \mu = 50, \sigma = 15

Find the probability that any shopper selected at random spends more than $80 per week?

This is 1 subtracted by the p-value of Z when X = 80. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 50}{15}

Z = 2

Z = 2 has a p-value of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that any shopper selected at random spends more than $80 per week.

Find the percentage of shoppers who are expected to spend between $30 and 80 per week?

The proportion is the p-value of Z when X = 80 subtracted by the p-value of Z when X = 30.

X = 80

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 50}{15}

Z = 2

Z = 2 has a p-value of 0.9772

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 50}{15}

Z = -1.33

Z = -1.33 has a p-value of 0.0918

0.9772 - 0.0918 = 0.8854

0.8854*100% = 88.54%

88.54% of shoppers are expected to spend between $30 and 80 per week.

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I need help pleas thank you
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The price-demand and cost functions for the production of microwaves are given as
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Answer:

<u>ALTERNATIVE 1</u>

a. Find the profit function in terms of x.

P(x) = R(x) - C(x)

P(x) = (-60x² + 275x) - (50000 + 30x)

P(x) = -60x² + 245x - 50000

b. Find the marginal cost as a function of x.

C(x) = 50000 + 30x

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c. Find the revenue function in terms of x.

R(x) = x · p

R(x) = x · (275 - 60x)

R(x) = -60x² + 275x

d. Find the marginal revenue function in terms of x.

R'(x) = (-60 · 2x) + 275

R'(x) = -120x + 275

The answers do not make a lot of sense, specially the profit and marginal revenue functions. I believe that the question was not copied correctly and the price function should be p = 275 - x/60

<u>ALTERNATIVE 2</u>

a. Find the profit function in terms of x.

P(x) = R(x) - C(x)

P(x) = (-x²/60 + 275x) - (50000 + 30x)

P(x) = -x²/60 + 245x - 50000

b. Find the marginal cost as a function of x.

C(x) = 50000 + 30x

C'(x) = 0 + 30 = 30

c. Find the revenue function in terms of x.

R(x) = x · p

R(x) = x · (275 - x/60)

R(x) = -x²/60 + 275x

d. Find the marginal revenue function in terms of x.

R(x) = -x²/60 + 275x

R'(x) = -x/30 + 275

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