Answer:
y<-5
Your Interval Notation would be an open circle and the arrow would be pointing to the left. (<-- (-6) --- (-5) --- (-4) -->) This will be your # line.
Step-by-step explanation:
9y+5(y+3) < 4y-35
1) Distribute the 5 in 5(y+3).
9y+5y+15 < 4y-35
2) Combine like terms. 9y and 5y.
9y+5y= 14y
14y+15 < 4y-35
3) MY TIP is to keep the variables on the left side, bc if you don't at the end you will have to flip the sign. so.. Subtract 4y from both sides
14y+15 < 4y-35
-4 -4
10y+15 < -35
3) Then you will subtract 15 from both sides
10y+15 < -35
-15 -15
10y < -50
4) Last is to divide to get your variable by itself.
10y < -50
÷10 ÷10
Answer : y < -5
Interval Solution: Open circle, -5 in the middle of the line and you will shade in the numbers to the left. .
