Ask question

Ask question

All categories

3 years ago

14

PLEASEE HURRY

1 answer:

DIA [1.3K]3 years ago

4 0

Answer:

2

Step-by-step explanation:

2

You might be interested in

Help Please I am not sure how to do this?

notsponge [240]

The answer should be Step 1; 3(1+2x)-2(x+1)+5

5 0

3 years ago

A train leaves San Diego at 1:00 pm. A second train leaves the same city in the same direction at 3:00 pm. The second train trav

Soloha48 [4]

Answer:

The speed of the first train is 45 mph and the speed of the second train is 75 mph

Step-by-step explanation:

Let x represent the speed of the first train in mph. Since the second train, is 30 mph faster then the first, therefore the speed of the second train is (x + 30).

The first train leaves at 1:00 pm, therefore at 6:00 pm, the time taken is 5 hours. Therefore the distance covered by the first train at 6:00 pm = x mph * 5 hours = 5x miles

The second train leaves at 3:00 pm, therefore at 6:00 pm, the time taken is 3 hours. Therefore the distance covered by the second train at 6:00 pm = (x + 30) mph * 3 hours = (3x + 90) miles

Since the second train overtakes the first at 6:00 pm, hence:

3x + 90 = 5x

2x = 90

x = 45

Therefore the speed of the first train is 45 mph and the speed of the second train is 75 mph (45 mph + 30 mph).

7 0

3 years ago

Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa

Artyom0805 [142]

Answer:

The height of the right trapezoid is $\frac{6}{5+\sqrt{3}}\ units$

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+DH+HA$

we have

$P=6\ units$

$AB=BC=CH=HA=x$ ---> because is a square

substitute

$6=x+x+CD+DH+x$

$6=3x+CD+DH$ -----> equation A

<em>In the right triangle CDH</em>

$sin(30\°)=\frac{CH}{CD}$

$sin(30\°)=\frac{1}{2}$

so

Remember that $CH=x$

$\frac{1}{2}=\frac{x}{CD}$

$CD=2x$

$tan(30\°)=\frac{CH}{DH}$

$tan(30\°)=\frac{\sqrt{3}}{3}$

so

$\frac{\sqrt{3}}{3}=\frac{x}{DH}$

$DH=x\sqrt{3}$

substitute the values in the equation A

$6=3x+CD+DH$ -----> equation A

$CD=2x$

$DH=x\sqrt{3}$

$6=3x+2x+x\sqrt{3}$

$6=5x+x\sqrt{3}$

$6=x[5+\sqrt{3}]$

$x=\frac{6}{5+\sqrt{3}}\ units$

5 0

3 years ago

Help im marking brainiest

saveliy_v [14]

Answer:

what's the question ????

6 0

3 years ago

Read 2 more answers

You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inch

Schach [20]

Answer:

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

Step-by-step explanation:

Given;

Length of the room = 12 feet 6 inches = 12.5 ft

Breadth of the room = 10 feet 6 inches= 10.5ft

Height of the room = 8 feet

Window = 4 ft by 3ft

door = 7ft by 3 ft

Wall paper = 30 inches by 30ft = 2.5ft by 30ft

The total area of the walls of the room is;

Area = Area of the four walls - Area of the two windows and a door.

A = 2LH + 2BH - Area of windows and door

A = 2(12.5×8) + 2(10.5×8) - 2(4×3) -(7×3)

A = 323ft^2

Allowing 10% waste, total area of wallpaper needed is;

At = 323 × 1.10 = 355.3ft^2

Area of wallpaper Aw= 2.5×30 = 75ft^2

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

3 0

3 years ago