Answer:
answer is 8! / (4! * 4!). Which gives a value of 70.
Explanation:
we have 8 places, we’re going to pick 4 places to put the zeros, it is 8! / (4! x 4!)
Answer:
Option 2 is correct.
Explanation:
Option 2 is correct because most of the components used in laptop is far different from Desktops. They are not able to fix in desktops. They are designed specially for laptops.
Answer:
#include <math.h>
#include <stdio.h>
#include <string.h>
#define BASE 3
#define NRQUESTIONS 15
void toABC(int n, char* buf, int base, int size) {
memset(buf, 'A', size);
buf[size] = 0;
while (n && size) {
buf[--size] = 'A' + (n % base);
n /= base;
}
}
int main()
{
char buf[16];
for (int i = 0; i < pow(BASE, NRQUESTIONS); i++) {
toABC(i, buf, BASE, NRQUESTIONS);
printf("%s\n", buf);
}
}
Explanation:
Assuming 3 is the number of possible answers to choose from for each question.
I tackled this by having an integer counter enumerate all values from 0 to 3^15, and then convert each integer to a base-3 representation, using ABC in stead of 012.
Answer:
- public class Main {
-
- public static void main (String [] args) {
- int[][] myArray = {{1,5,6}, {7, 9, 2}};
- fixArray(myArray, 1, 2, 12);
-
- System.out.println(myArray[1][2]);
- }
-
-
- private static void fixArray(int[][] array, int row, int col, int value){
- array[row][col] = value;
- }
- }
Explanation:
The solution code is written in Java.
Firstly, create the method fixArray with that takes four inputs, array, row, col and value (Line 11). Within the method body, use row and col as index to address a particular element from array and set the input value to it (Line 12).
Next, we test the method in the main program using a sample array (Line 4) and we try to change the row-1 and col-2 element from 2 to 12 (Line 5).
The print statement in Line 7 will display 12 in console.
Answer:
this worksheet can be found online
Explanation:
