Answer:
Replace /* Your solution goes here */ with:
cin>>matchValue;
numMatches = 0;
for (i = 0; i < userValues.size(); ++i) {
if(matchValue == userValues.at(i))
{
numMatches++;
}
}
Explanation:
This line gets input for matchValue
<em>cin>>matchValue;
</em>
This line initializes numMatches to 0
<em>numMatches = 0;
</em>
The following iteration checks for the number of matches (numMatches) of the matchValue
<em>for (i = 0; i < userValues.size(); ++i) {
</em>
<em>if(matchValue == userValues.at(i))
</em>
<em>{
</em>
<em> numMatches++;
</em>
<em>}
</em>
<em>}
</em>
<em>See Attachment for full source code</em>
Answer:
Everything.It doesn't matter the information because there's always a way to plagiarize.No matter what the information, always, ALWAYS, cite the source.
Explanation:
?? it should be radio waves but i guess the next best thing is microwaves
It is called a Cooperative program
A Cooperative program refers to a combination of both academic study and vocational activities in one curriculum of education. The purpose of this program is to provide the students with both knowledge in theory and practical skills that make them more prepared in the real world.
In computers we use: decimal constantly, hexadecimal daily, octal weekly and binary monthly. Decimal is base 10, hexadecimal is base 16, octal is base 8 and binary is base 2.
To convert binary to decimal, simply add the magnitudes of the digits that are set.
