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lukranit [14]
3 years ago
9

I need help please and thank you

Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
X=6 is the ansssswerrr
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jerry has 60 coins consisting of quarters and dimes. The coins combined value is $9.45. Find out how are quarters and how many a
jekas [21]
Eq. 1 .10x + .25y = 9.45
Eq. 2 x + y = 60 rewrite as x = 60 - y and substitute into equation 1.

.10(60 - y) + .25y = 9.45
6 - .1y + .25y = 9.45
6 + .15y = 9.45
.15y = 3.45
y = 23
60 - 23 = 37

23 quarters
37 dimes


23* .25 = 5.75
37 * .1 = 3.70
5.75 + 3.70 =9.45
7 0
4 years ago
A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the box is e
mojhsa [17]

Answer:

V = 4/3 x pi x r^3

972 x pi= 4/3 x pi x r^3

729 = r^3

The cubic root of 729 is 9 because 9 x 9 x 9 = 729.

The radius is 9 inches, and the diameter is 18 inches.

The volume of the box is 18 in x 18 in x 18 in or 5832 in.³.

Step-by-step explanation:

7 0
3 years ago
What is 82.68 divide by 1,000<br>​
serg [7]

Answer:

0.08268 is what I got

Step-by-step explanation:

I hope it correct

8 0
3 years ago
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What is the sun of this question somebody tell me
Liono4ka [1.6K]

Answer:

  • 2/10 +28/100
  • 20+28/100
  • 48/100
  • 12/25
3 0
2 years ago
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Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).
baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

Step-by-step explanation:

There are two kew parameters for a sphere: Center (h, k, s) and Radius (r). The radius is the midpoint of the line segment between endpoints. That is:

C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2}   \right)

C(x,y,z) = (1,-2,4)

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}

r = 10\sqrt{3}

The general formula of a sphere centered at (h, k, s) and with a radius r is:

(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is (x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30.

8 0
3 years ago
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