The answer is 1224. You do 70.5 + 65.5, divided by two, then you take that answer and multiply by 18 to get 1224
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
Answer:
Take 7.1-4.9=x
Step-by-step explanation:
Answer:
I think it is c 266.3 cubic centimeters
Step-by-step explanation:
Hope this helps
Answer:
I prefer solving problens with fractions because it's easier to add them and you can turn them in to mixed numbers. Hope this helps you!
