What are the solution(s) to the quadratic equation 40 − x2 = 0?

2 answers:

8 0

$40-x^2=0\ \ \ |add\ x^2\ to\ both\ sides\\\\x^2=40\iff x=\pm\sqrt{40}\\\\x=-\sqrt{4\cdot10}\ or\ x=\sqrt{4\cdot10}\\\\x=-\sqrt4\cdot\sqrt{10}\ or\ x=\sqrt4\cdot\sqrt{10}\\\\\boxed{x=-2\sqrt{10}\ or\ x=2\sqrt{10}}$

ohaa [14]3 years ago

5 0

$40-x^2=0\\
x^2=40\\
x=-\sqrt{40} \vee x=\sqrt{40}\\
x=-2\sqrt{10} \vee x=2\sqrt{10}$

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4 0

3 years ago

Read 2 more answers

6. What is the slope of the line given by the equation y = 4x +12?

quester [9]

Answer:

Step-by-step explanation:

y = 4x + 12

In y = mx+b

The coefficient of x (m) is the slope.

So the slope is 4

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