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3 years ago

Write an equation to solve for x, then solve for x. The whole question is in the picture.

Mathematics

1 answer:

UNO [17]3 years ago

4 0

Answer:

12x = 60 x = 5

Step-by-step explanation:

2 (2x + 4x) = 2 (6x) = 12x

the perimeter is 12x and 60 is the perimeters value so you divide 60 by 12 and get 5

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Please, I need an answer to this question urgently.

Blababa [14]

Answer:

156

Step-by-step explanation:

While solving we will have to use the area formula of the rectangle, which is :A=w*l ; length*width=A.

Steps:
1)let’s consider that the shape is a full rectangle. => 16*12=192.

2)9*2=18 -> 18*2=36

3)192-36=156.

4 0

3 years ago

Read 2 more answers

Need an answer thanks

artcher [175]

Answer:

Step-by-step explanation:

8 0

4 years ago

Why is it important to know the shape of the base of the pyramid

Wewaii [24]

Answer:The pyramid had sloping sides so that the dead pharaoh could symbolically climb to the sky and live forever. The pyramid represented the rays of the Sun I hope this helps

Step-by-step explanation:

7 0

3 years ago

Jewel is 7 years old and John is 16 years younger than Dave. One year ago, Dvae's age was twice the sum of Jewel's and John's ag

ivanzaharov [21]

Answer:

Jewel is 7 years old

John is 1 year old

Dave is 17 years old

Step-by-step explanation:

From the question we are told that:

Jewel age is $J=7 years$

John age $J'=(D-16)years$

Dave's age a Year ago

$D-1=2(J-1+J'-1)$

So that Dave.s age this Year could be

$D=2((J-1)+(J'-1))+1$

Simplifying Equation for Dave's age we have

$D=2((7)-1+(D-16)-1)+1$

$D=2(6+D-15)+1$

$D=2(D-9)+1$

$D=2D-18+1$

$D=17 Years$

Dave is 17 years old

Therefore

Johns age is

$J'=(D-16)$

$J'=17-16$

$J'=1year old$

John is 1 year old

7 0

3 years ago

The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act

cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean $\mu$ , the actual temperature of the medium, and standard deviation $\sigma$ .