It will equal
x(5)(6)=30x
5 and 5/10s sounds like 5.5 so I'd do 5.5+0.02=5.52
<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
Answer:
12;16
Step-by-step explanation:
The Pythagorean theorem states that
a^2+b^2=c^2 where a and b are legs of a triangle, and c is the hypotenuse.
This means that we have to find 2 values that once squared, add up to 400. (20^2)
Based on this, we can use the values of 12 and 16 to satisfy this.
12^2+16^2=144*256=400
Therefore, the legs of the triangle are 12 and 16.
