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Grace [21]
3 years ago
13

Miranda wants to give her 14-year-old daughter $20,000 when she turns 18. How much does she need to put in the bank now if the i

nterest rate is 10 percent per year?
Mathematics
1 answer:
Eddi Din [679]3 years ago
3 0
20,000 = P ( 1 + 0.1 )^4
20,000 = P * 1.1^4
20,000 = P * 1.461
P = 20,000 : 1.461 ≈ $13,689.25
Answer: Miranda needs to put now in the bank $13,689.25 
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When ordering a student desk priced at $69.00, the shipping charges are 6%. What is the total cost of the desk?
Wittaler [7]
Since the desk is $69.00 and the shipping charges are 6%

69*.06= 4.14

Your tax would be $4.14 so,

$4.14+$69.00= A total of $73.14
7 0
3 years ago
Read 2 more answers
Can i have help on this q plz
lukranit [14]

Answer:

No, they will need an additional £34 to stay the planned 10 nights.  

Step-by-step explanation:

Attached screenshot of a spreadsheet.

The cost for 10 nights for the 2 people is £100.

The tent site rental (over 10m^2) for 10 nights is £150.

Savings for the two over the 9 weeks is £216.

They will need an additional £34 to camp as planned.  

I suggest fibbing about the extra 0.5m^2 needed for the tent site.  That will reduce the bill by £30, so they are only £4 short.  Time to make a couple of friends.

3 0
3 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
4 years ago
I WOULD LIKE HELP WITH THIS PLEASE!!!
Ainat [17]

Answer:

the answer would be 80 :)

6 0
3 years ago
Can anyone help me with this algebra problem ?
Ann [662]
The top right one is not a function
7 0
3 years ago
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