<span><span>0.1n</span>=89.5</span>
<span /><span>Step 1: Divide both sides by 0.1.</span>
<span><u>Answer: </u><span><span>n=89</span></span></span>
<span><span><span /><span><span><span><span>(10)</span><span>(3)</span></span>n</span>=630</span></span></span>
<span><span><span /><span><span>Step 1: Simplify both sides of the equation.</span></span></span></span>
<span><span><span /></span></span>30n= 630
step1: divide both sides by 30.
<u>Answer</u>:<u /> n= 21
Answer: The required equation is 
and the number of fishes in the pond on June 1 = 115
Step-by-step explanation:
Given: The number of fishes in pond on July 1 = 63
Also, it is said that the number of fishes in pond on July 1 is 52 fewer(lesser) than the number of fishes in pond on June 1.
Let f be the number of fishes in pounds on June 1.
then the required equation will be
Now, add 52 on both the sides of the equation, we get
Answer:
16 (positive 16)
Step-by-step explanation:
Postive is because the first change is positive and the school bell is out sorry
<u>Markup . . . </u>
-- I buy a cabbage for $1.00 and put it on the shelf in my store.
-- I mark it up 100% . . . I offer it for sale for $2.00
-- I mark it up 200% . . . I offer it for sale for $3.00 .
<u>Markdown . . .</u>
-- I buy a cabbage for $1.00 and put it on the shelf in my store.
-- I mark it down 100% . . . I sell it for zero. (I give it away.)
-- I mark it down 200% . . . I give you $1.00 to take it home with you.
Answer:
n-2<9
Step-by-step explanation:
9+2=11. n<11
