Answer:
Step-by-step explanation:
You could multiply all of equation A by 1/6 and all of equation b by -1/4 to get
A. x-3/2y=-1/3 and B. x+1/4y=/5/4, then subtract the equations from each other to solve
Answer:
The answer is 4
Step-by-step explanation:
Solution:
The gas can is filled at the rate of 320 cubic inches per minute.
The can is 10 inches long, 8 inches wide, and 12 inches high.
So volume of the can=10 in*8 in *12 in

Time required to fill the can
Hence Time required to fill the can =3 minutes.

bear in mind that, though the square has two valid roots, one negative and one positive, the hypotenuse is just a radius distance, and therefore is never negative.