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Agata [3.3K]
3 years ago
10

Perform the indicated operation.(3/a+2) + (4/a-5)

Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

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<u>Given</u>:

Line m is parallel to line n.

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Substituting the measures of ∠1 and ∠2, we get;

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The measure of ∠1 can be determined by substituting x = 10 in the measure of ∠1

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