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Masteriza [31]
3 years ago
8

I need help with number 1-4 I don’t understand..

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

  1. 109°, obtuse
  2. 131°, obtuse
  3. 53°, acute
  4. 124°, obtuse

Step-by-step explanation:

You are exected to know the relationships of angles created where a transversal crosses parallel lines.

  • Corresponding angles are equal (congruent).
  • Adjacent angles are supplementary, as are any linear pair.
  • Opposite interior (or exterior) angles are equal (congruent).

The appearance of the diagram often gives you a clue.

You also expected to know the name (or category) of angles less than, equal to, or greater than 90°. Respectively, these are <em>acute</em>, <em>right</em>, and <em>obtuse</em> angles.

1. Adjacent angles are supplementary. The supplement of the given angle is 109°, so x will be obtuse.

2. Opposite exterior angles are equal, so y will be 131°. It is obtuse.

3. Opposite interior angles are equal, so w will be 53°. It is acute.

4. Corresponding angles are equal, so x will be 124°. It is obtuse.

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Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

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Step-by-step explanation:

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Write a two column proof for the following conjecture. Statements and reasons
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<span>Information is given(reasons are in the parenthesis) 

Angle A and angle B are supplementary. Angle B and Angle C are supplementary  (given)


DC is parallel to AB (consecutive interior angles are supplementary )
BC is parallel to AD (consecutive interior angles are supplementary)

ABCD is a parallelogram (definition of parallelogram, has to pairs of parallel sides)</span>
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find the volume of a rectangular block of ice 2 feet by 3 and 1/2 feet by 1 and 1/2 feet the volume of the rectangular block of
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Answer:

V = 10 1/2 ft³

Step-by-step explanation:

V = length • width • height

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8 0
2 years ago
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?.
tino4ka555 [31]

The probability that the cube never lands on 3 is (D) 23.3%.

<h3>What is probability?</h3>
  • A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.

To find the probability that the cube never lands on 3:

Given -

  • Number cube toss = 8

Required

  • Probability of not landing on 3.

First, we need to get the probability of landing on 3 in a single toss.

For a number cube,

  • n(3) = 1 and n(total) = 6

So, the probability is P(3) = 1/6

First, we need to get the probability of not landing on 3 in a single toss.

Opposite probability = 1.

  • So, P(3) = P(3') = 1.

Make P(3') the subject of the formula.

  • P(3') = 1 - P(3)
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In 8 toss, the required probability is (P(3'))⁸

This gives:

  • P = (5/6)⁸
  • P = 390625/1679616
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Approximate to 1 decimal place, P = 23.3%.

Therefore, the probability that the cube never lands on 3 is (D) 23.3%.

Know more about probability here:

brainly.com/question/25870256

#SPJ4

The correct question is given below:
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?

A. 6.0%

B. 10.4%

C. 16.7%

D. 23.3%

5 0
1 year ago
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