Answer:
Euler's method is a numerical method used in calculus to approximate a particular solution of a differential equation. As a numerical method, we have to apply the same procedure many times, until get the desired result.
In first place, we need to know all the values the problem is giving:
- The step size is 0.2; h = 0.2. This step size is a periodical increase of the x-variable, which will allow us to calculate each y-value to each x.
- The problem is asking the solution y(1), which means that we have to find the y-value assigned for x = 1, through the numerical method.
- The initial condition is y(0) = 9. In other words,
.
So, if the initial x-value is 0, and the step size is 0.2, the following x-value would be: 
; then 
; 
; and so on.
Now, we have to apply the formula to find each y-value until get the match of 
, because the problem asks the solution y(1).
According to the Euler's method:
Where 
, and 
; 
.
Replacing all values we calculate the y-value assigned to 
:
.
Now, 
, 
. We repeat the process with the new values:
Then, we repeat the same process until get the y-value for 
, which is 
, round to four decimal places.
Therefore, 
.
It's not hard to find one of those, since there are
an infinite number of them. Here are a few:
18.55000001
18.56
18.57
18.58
18.59
18.591
18.59100001
18.59100002
18.59100003
18.59100004
18.59100005
18.5910006
18.591007
18.59108
18.5919
18.59191
18.59192
18.59193
.
.
etc.
Slope = (-3 - r) / (2 - 5)
Slope = <span>(-3 - r) / -3 = 4/3
-(-3 - r) = 4
3 + r = 4
r = 4 - 3
r = 1 option b.</span>
Answer:
y = -13x + 55
Step-by-step explanation:
perpendicular formula : m1 × m2 = -1
y = -13x + 4
now we take the grafient of the equation which is 13 :
m × 13 = -1
m = -13
so now we hv a new gradient then we can find the equation use the formula y = mx + c :
m = -13 point = ( 4 , 3 )
sub them into the formula,
3 = -13 (4) + c
3 = -52 + c
3 + 52 = c
55 = c
c = 55
now we rewrite again the c and the m to become a complete equation : y = -13x + 55
Answer:
use desmos to figure it out.
