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Oksana_A [137]
3 years ago
10

Graph the solution x

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0

Answer:

I think you need to put more info

Step-by-step explanation:


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Evaluate the limit 12n^3 - 2n^2 + 9 / 4n^3
geniusboy [140]

Answer:

3

Step-by-step explanation:

Evaluate the limit n - > ∞ 12n^3 - 2n^2 + 9 / 4n^3

Divide the expression by the highest power of n to have

limit n - > ∞ 12n³/n³ - 2n²/n³ + 9/n³ / 4n³/n³

= limit n -  > ∞12 - 2/n + 9/n³ / 4

Substitute the value of n

= 12 - 2/∞ + 9/∞³ / 4

Since a/∞ = 0

The expression becomes;

= 12 - 0+ 0/4

= 12/4

= 3

Hence the required limit is 3

7 0
3 years ago
Find the equation to the line below.
kodGreya [7K]

Answer:

y=3/2x +2

Step-by-step explanation:

Rise/run + y-intercept

6 0
2 years ago
Read 2 more answers
PLEASE HURRYYYYYYYYYY!!!!!!!!<br><br><br> In OD, AB = CB and marc CE - 52. Find mZBCE. (See picture)
frozen [14]

Answer:

A. 109

Step-by-step explanation:

We know that since AB = CB, then ΔABC is isosceles.

Since AC, one of the sides of ΔABC, is on the diameter of circle D, by definition, we know that ΔABC is also a right triangle. Thus, if ΔABC is an isosceles right triangle, then ∠BAC = ∠BCA = 45°.

Draw a line connecting D to B so that we now have isosceles triangle BDC. Since arc BC is 52°, by definition of central angles, ∠BDC is also equal to 52°. Then, ∠DBC = ∠DCB = (180 - 52)/2 = 64°.

∠BCE = ∠DCB + ∠BCA

∠BCE = 64 + 45 = 109°

The answer is thus A.

<em>~ an aesthetics lover</em>

3 0
3 years ago
is the volume of a cylinder which has the same radius but twice the height greater or less than the original cylinder
blondinia [14]
Definitely, its volume is greater than the original cylinder. Hope it help!
5 0
3 years ago
Study guide help?
Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Garrett achieves a field goal is independent of each kick.  Hence X no of kicks is binomial with p = 0.83, and q =0.17

No of trials 3

Hence X can take values as 0 ,1,2,3 and

P(X=r) = 4Cr(0.83)^r (0.17)^{4-r}

, r=0,1,2,3

Using the above we obtain prob distribution as

X         0                  1           2            3                

P(X)   0.0049   0.0720   0.3513   0.5718

P(X>=2) =P(X=2,3,4) =0.9231

-----------------------------------------

2) Z value for company A =\frac{260-272}{5.4} =-2.22

Z value for company B = (260-249)/3.8 =2.89

From z value probablility is more for company A as

P(Z>-2.22) >P(Z>2.89)

8 0
3 years ago
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