Definition:
A function is "even" when f(x) = f(−x) for all x.
Geometrically speaking, the graph face of an even function is symmetric with respect to the y-axis, meaning that its graph remains unchanged after reflection about the y-axis.
If point (6, 8) is one the points on the graph of f(x), then f(6)=8 and since function is even, you can state that f(-6)=f(6)=8. This means that point (-6,8) must also be a point on the graph. Geometrically it means that the output of a negative x-value and its opposite is the same.
Answer: correct choice is A.
Answer:
Step-by-step explanation:
The center of the circle is the midpoint of the two end points of the diameter.
Formula
Center = (x2 + x1)/2 , (y2 + y1)/2
Givens
x2 = 4
x1 = - 10
y2 = 6
y1 = - 2
Solution
Center = (4 - 10)/2, (6 - 2)/2
Center = -6/2 , 4/2
Center = - 3 , 2
So far what you have is
(x+3)^2 + (y - 2)^2 = r^2
Now you have to find the radius.
You can use either of the endpoints to find the radius.
find the distance from (4,6) to (-3,2)
r^2 = ( (x2 - x1)^2 + (y2 - y1)^2 )
x2 = 4
x1 = -3
y2 = 6
y1 = 2
r^2 = ( (4 - -3)^2 + (6 - 2)^2 )
r^2 = ( (7)^2 + 4^2)
r^2 = ( 49 + 16)
r^2 = 65
Ultimate formula is
(x+3)^2 + (y - 2)^2 = 65
The radius is √65 = 8.06
Answer:
268+v2)3+p=8 =p=−3v2−796
Step-by-step explanation:
Let's solve for p.
(268+v2)(3)+p=8
Step 1: Add -804 to both sides.
3v2+p+804+−804=8+−804
3v2+p=−796
Step 2: Add -3v^2 to both sides.
3v2+p+−3v2=−796+−3v2
p=−3v2−796
<em><u>Hope this helps.</u></em>
Answer:
2.76
Step-by-step explanation:
smort
Answer:
(C)72.4 in
Step-by-step explanation:
Given an acute triangle in which the longest side measures 30 inches; and the other two sides are congruent.
Consider the attached diagram
AB=BC=x
However to be able to solve for x, we form a right triangle with endpoints A and C.
Since the hypotenuse is always the longest side in a right triangle
Hypotenuse, AC=30 Inches
Using Pythagoras Theorem
Therefore, the smallest possible perimeter of the triangle
Perimeter=2x+30
=2(21.21)+30
=42.42+30
=72.4 Inches (rounded to the nearest tenth)
