Answer:
593 
Step-by-step explanation:
3.14 × 
= 907.46
3.14 × 
= 314
907.46 - 314 = 593.46
To solve this problem, we first have to convert 5 1/2 into an improper fraction. To do this, we multiply the unit (5) times the denominator (2) and then add the numerator (1) to the product, while still keeping the same denominator.
(5 * 2) + 1 = 10 + 1 = 11/2
Now, this makes our expression: 11/2 - 2/3
Next, we have to find a common denominator for 2 and 3 by finding their shared LCM, or least common multiple. In this case, the LCM is 6. This means that we are going to convert both of the fractions in the expression into fractions with the denominator 6, so that we can easily compute the subtraction.
11 * 3 / 2 * 3 - 2 * 2 / 3 * 2
33/6 - 4/6
Now, we can simply subtract the numerators to find our final answer.
29/6
Your final answer is 29/6.
Hope this helps!
Answer: Betsy is incorrect.
Step-by-step explanation:
The area of a trapezoid is a+b/2 multiplied by h.
First, we should do 5+8/2= 6.5
Next, we multiply 6.5 with 4 because 4 is the height of the trapezoid.
6.5 times 4= 26
Betsy thought the answer was 52, but it is 26 so she is incorrect.\
I hope this helps, may god bless you! :)
16.6 with a line on top of 6. When you divide 50 by 3 you get 16.6 a repeating decimal.you would round and get 17. I think it's correct!!
3.1 a) x = 6 / 5 or x = 2, b) x = - 3 / 2 or x = - 1 / 4, c) x = - 3 or x = 2, d) x = 1 or x = - 2.
3.2 a) x = 9 or x = - 3, b) x = 1 or x = - 1 / 4, c) x = - 3 or x = - 5 d) x = 8 or x = - 18
<h3>How to solve algebraic problems by appying absolute value properties</h3>
In this question we have eight expressions involving <em>absolute value</em> expressions, which can be solved by using the following procedure:
3.1 a) |(1 / 2) · x| = 3 - 2 · x
For x ≥ 0:
(1 / 2) · x = 3 - 2 · x
(5 / 2) · x = 3
x = 6 / 5
For x < 0:
- (1 / 2) · x = 3 - 2 · x
(3 / 2) · x = 3
x = 2
b) |x - 1| = 3 · x + 2
For x ≥ 1:
x - 1 = 3 · x + 2
2 · x = - 3
x = - 3 / 2
For x < 1:
- x + 1 = 3 · x + 2
4 · x = - 1
x = - 1 / 4
c) |5 · x| = x - 12
For x ≥ 0:
5 · x = x - 12
4 · x = - 12
x = - 3
For x < 0:
- 5 · x = x - 12
6 · x = 12
x = 2
d) |7 - x| = 5 · x + 1
For x ≤ 7:
7 - x = 5 · x + 1
6 · x = 6
x = 1
For x > 7:
x - 7 = 5 · x + 1
4 · x = - 8
x = - 2
3.2 a) |9 + x| = 2 · x
For x ≥ - 9:
9 + x = 2 · x
x = 9
For x < 9:
- 9 - x = 2 · x
3 · x = - 9
x = - 3
b) |5 · x| - 3 · x = 2
For x ≥ 0:
|5 · x| = 2 + 3 · x
5 · x = 2 + 3 · x
2 · x = 2
x = 1
For x < 0:
- 5 · x = 2 + 3 · x
- 8 · x = 2
x = - 1 / 4
c) |x + 6| - 9 = 2 · x
For x ≥ - 6:
x + 6 - 9 = 2 · x
x - 3 = 2 · x
x = - 3
For x < - 6:
- x - 6 - 9 = 2 · x
- x - 15 = 2 · x
3 · x = - 15
x = - 5
d) |2 · x - 3| + x = 21
For x ≥ 3 / 2:
2 · x - 3 + x = 21
3 · x = 24
x = 8
For x < 3 / 2:
- 2 · x + 3 + x = 21
- x = 18
x = - 18
To learn more on absolute values: brainly.com/question/1301718
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