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Nadusha1986 [10]
2 years ago
12

Find the value b-7 when b=20

Mathematics
2 answers:
PtichkaEL [24]2 years ago
8 0

Answer:

13

Step-by-step explanation:

20-7 hope this helps :)

allsm [11]2 years ago
4 0

Replace b in the equation with 20 and solve.

B-7 = 20-7 = 13

The answer is 13

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Verizon [17]

Answer:

48

Step-by-step explanation:

You can do it with cross multiplication

6 0
2 years ago
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Determine whether f(x) = 5x+1/x and g(x)= x/ 5x+1 are inverse functions explain how you know. please explain in steps or worded
Len [333]

Hello from MrBillDoesMath!

Answer:

No


Discussion:

If the functions are inverses, then f(g(x)) = x  for appropriate x. Consider x = 1.

g(1) = 1/ (5(1) + 1) = 1/6

f(g(1)) = f (1/6) =  5(1/6) + 1/ (1/6) = 5/6 + 6 = 6 5/6   <> 1

Conclusion: f(g(1)) <> 1 so the functions are not inverses


Thank you,

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7 0
3 years ago
How many years will it take James to recover his investment?
My name is Ann [436]
I don’t think anyone knows this one not even James
6 0
2 years ago
Lines k and n intersect on the y-axis
avanturin [10]

a) The equation of line k is:

y = -\frac{202}{167}x + \frac{598}{167}

b) The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

The equation of a line, in <u>slope-intercept formula</u>, is given by:

y = mx + b

In which:

  • m is the slope, which is the rate of change.
  • b is the y-intercept, which is the value of y when x = 0.

Item a:

  • Line k intersects line m with an angle of 109º, thus:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

In which m_1 and m_2 are the slopes of <u>k and m.</u>

  • Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}

  • The tangent of 109 degrees is \tan{109^{\circ}} = -\frac{29}{10}
  • Thus, the slope of line m is found solving the following equation:

\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}

-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}

m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2

m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}

\frac{167m_2}{80} = \frac{-202}{80}

m_2 = -\frac{202}{167}

Thus:

y = -\frac{202}{167}x + b

It goes through point (-2,6), that is, when x = -2, y = 6, and this is used to find b.

y = -\frac{202}{167}x + b

6 = -\frac{202}{167}(-2) + b

b = 6 - \frac{404}{167}

b = \frac{6(167)-404}{167}

b = \frac{598}{167}

Thus. the equation of line k, in slope-intercept formula, is:

y = -\frac{202}{167}x + \frac{598}{167}

Item b:

  • Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

-\frac{202}{167}m = -1

m = \frac{167}{202}

Then

y = \frac{167}{202}x + b

Also goes through point (-2,6), thus:

6 = \frac{167}{202}(-2) + b

b = \frac{(2)167 + 202(6)}{202}

b = \frac{1546}{202}

The equation of line j is:

y = \frac{167}{202}x + \frac{1546}{202}

A similar problem is given at brainly.com/question/16302622

7 0
2 years ago
Please help …………………….
Mars2501 [29]

9514 1404 393

Answer:

  (-3, 3)

Step-by-step explanation:

The blanks are trying to lead you through the process of finding the point of interest.

__

The horizontal distance from T to S is <u> 9 </u>. (or -9, if you prefer)

The ratio you're trying to divide the line into is the ratio that goes in this blank:

Multiply the horizontal distance by <u> 2/3 </u>. (9×2/3 = 6)

Move <u> 6 </u> units <u> left </u> from point T.

The vertical distance from T to S is <u> 6 </u>.

Multiply the vertical distance by <u> 2/3 </u>. (6×2/3 = 4)

Move <u> 4 </u> units <u> up </u> from point T.

__

Point T is (3, -1) so 6 left and 4 up is (3, -1) +(-6, 4) = (3-6, -1+4) = (-3, 3). The point that is 2/3 of the way from T to S is (-3, 3).

3 0
2 years ago
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