Answer:


Step-by-step explanation:
Given
See attachment for kite dimension
Required
Determine the width and the area
From the attachment, the height of the kite is:


The width which is half the height is:



The area is:




1) Determine the horizontal force, Fx, exerted by the block on Usain
cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N
2) Determine the Impulse of that force on Usain.
I = F*t = 1597.48N * 0.32s = 511.19 N*s
3) Determine change in momentum of Usain, Δp
Δp = I = 511.19 N*s
4) Find change if velocity
Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s
Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s
Answer: 5.94 m/s
Answer:
A. f(x)=9x+4
Step-by-step explanation:
Function is f(x) =9x+4, because if x=1, then f(1)=9*1+4=9+4=13;
if x=5,then f(5)=9*5+4=45+4=49
Answer:
18
Step-by-step explanation:
20/2 + 8
Divide the numerator and denominator by 2
20 / 2
2 / 2
Divide the numbers
10
2 / 2
=
10 / 1
Any expression divided by 1 remains the same
10 + 8 = 18
2r+7+2n+n2
Because I combined the ones with like terms.