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4 years ago

Jalen had 4 2/3 pounds of modeling clay and used 3 1/2 pounds for a craft project. How many pounds of clay were not used?

Mathematics

1 answer:

Leto [7]4 years ago

3 0

I hope this helps!

The answer would be 1 1/6

just the subtract the two mixed numbers and your done

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A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour how many

Burka [1]

Answer:

2 1/4 times

Step-by-step explanation:

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour. how many times as long in the morning did he work in the afternoon

Note that:

1 hour = 60 minutes

In the moring he worked 2/5 of an hour.

= 2/5 × 60 minutes

= 24 minutes

In the afternoon he worked for 9/10 of an hour

Hence:

9/10 × 60 minutes

= 54 minutes

How many times as long in the morning did he work in the afternoon?

This is calculated as number of minutes worked in the afternoon ÷ Number of minutes worked in the morning

= 54 minutes/24 minutes

= 2 6/24

= 2 1/4 times

4 0

3 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B3%7D%20-%5Cfrac%7B3-2x%7D%7B6%7D%3D%5Cfrac%7B5%7D%7B2%7D%2

mestny [16]

Answer:

x = - $\frac{3}{11}$

Step-by-step explanation:

Given

$\frac{x}{3}$ - $\frac{3-2x}{6}$ = $\frac{5}{2}$ x

Multiply through by 6 to clear the fractions

2x - (3 - 2x) = 15x ← distribute and simplify left side

2x - 3 + 2x = 15x

4x - 3 = 15x ( subtract 4x from both sides )

- 3 = 11x ( divide both sides by 11 )

- $\frac{3}{11}$ = x

7 0

3 years ago

Read 2 more answers

A town orchestra is holding auditions for 3 new flute players and 4 new trumpet players. If8 flutists try out, and 11 trumpeters

tensa zangetsu [6.8K]

A town orchestra needs 3 new flute players and 4 new trumpet players. 8 flutists and 11 trumpeters try out, then the orchestra should select 3 flutists from 8 and 4 trumpeters form 11.

They can choose 3 flutists from 8 in

$C_8^3=\dfrac{8!}{3!(8-3)!}=\dfrac{8!}{3!\cdot 5!}=\dfrac{1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8}{1\cdot 2\cdot 3\cdot 1\cdot 2\cdot 3\cdot 4\cdot 5} =56$ ways.

They can choose 4 flutists from 11 in

$C_{11}^4=\dfrac{11!}{4!(11-4)!}=\dfrac{11!}{4!\cdot 7!}=\dfrac{1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8\cdot 9\cdot 10\cdot 11}{1\cdot 2\cdot 3\cdot 4\cdot 1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7} =330$ ways.