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Zanzabum
3 years ago
5

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour how many

times as long in the morning did he work in the afternoon
Mathematics
1 answer:
Burka [1]3 years ago
4 0

Answer:

2 1/4 times

Step-by-step explanation:

A builder was building a fence. In the moring he worked 2/5 of an hour. In the afternoon he wirked for 9/10 of an hour. how many times as long in the morning did he work in the afternoon

Note that:

1 hour = 60 minutes

In the moring he worked 2/5 of an hour.

= 2/5 × 60 minutes

= 24 minutes

In the afternoon he worked for 9/10 of an hour

Hence:

9/10 × 60 minutes

= 54 minutes

How many times as long in the morning did he work in the afternoon?

This is calculated as number of minutes worked in the afternoon ÷ Number of minutes worked in the morning

= 54 minutes/24 minutes

= 2 6/24

= 2 1/4 times

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Step-by-step explanation:

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3 years ago
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In a group of 60 workers, the average salary is $80 a day per worker. if some of the workers earn $75 a day and all the rest ear
Softa [21]

The total number of workers that earn $75 per day is 48

<h3>What is average salary?</h3>

The average salary is calculated based on reported salaries of respondents. The average salary definition is to add the salaries in the sample together, then divide by the number of respondents.

Given that:

In a group of 60 workers, the average salary is $80 a day per worker.

If some of the workers earn $75 a day and all the rest earn $100 a day.

Let 'x' be the total number of workers that earn $75 per day.

So, the total number of workers that earn $100 per day is (60 - x).

As the average salary of 60 workers is $80.

Then,

\frac{75x + 100(60-x)}{60} =80

or, 75 x + 6000- 100x = 80*68

or, -25x= -1200

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So, the total number of workers earn $75 per day is 48.

Learn more about the concept here:

brainly.com/question/21835898

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3 years ago
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Answer:

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Answer:

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