Answer: The relationship between the weight of a stack of standard 8.5x11 copier paper vs number of sheets of paper is proportional.
Step-by-step explanation:
Let us assume here, in this situation that each page has the same weight so if i want to find the weight of the complete stack, I will multiply the number of sheets of paper by the weight of a single sheet of paper.
Answer:
Step-by-step explanation:
Set s(t) = 0 which means it hits the ground. The formula doesn't fit the parameters given as it shows that the pitcher is standing on something 37 feet high.
<span>s(t)=-16t^2+140t+37 and has an initial velocity of 140.
Graphing or solving this, t= 9 seconds when it hits the ground.
The velocity V(t) is the derivative of s(t)
V(t) = -32t+140
V(9) = -148 ft/second which is going down
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Answer:
The given points are;
A(3, 5), B(5, 3), C(2, 2)
The given transformation is;
Answer:
379.94 mi²
Step-by-step explanation:
The area of a circle can be figured out with this formula: πr² (3.14 is π here, as it says in the directions).
We know the diameter is 22 miles. Divide that by 2 to get a radius of 11 miles.
The equation now becomes
3.14(11²)
11 squared is 121.
3.14(121)
I recommend splitting the 121 into 100, 20, and 1.
(3.14 * 100) + (3.14 * 20) + (3.14 * 1)
Multiply 3.14 by 100, 20, and 1.
314 + 62.8 + 3.14
Add 314 and 62.8.
376.8 + 3.14
Add 376.8 and 3.14
379.94 mi² is the area of a circle with a 22-mile diameter.
