9514 1404 393
Answer:
₹14000
Step-by-step explanation:
Let c represent the cost price, and m represent the marked price.
c × (1 +40%) = m
m × (1 -15%) - c = ₹1900
Using the first expression for m, the second equation becomes ...
1.40c×0.85 -c = ₹1900
0.19c = ₹1900
c = ₹1900/0.19 = ₹10000
Then the marked price was ...
m = 1.40c = 1.40×₹10000 = ₹14000
The marked price was ₹14000.
_____
The selling price was ₹11900.
The mass of radioactive material remaining after 50 years would be 48.79 kilograms
<h3>How to determine the amount</h3>
It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.
Given the radioactive decay formula as
m(t)=120e−0.018t
Where
t= 50 years
m(t) is the remaining amount
Substitute the value of t


Find the exponential value
m(t) = 48.788399
m(t) = 48.79 kilograms to 2 decimal places
Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms
Learn more about half-life here:
brainly.com/question/26148784
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Answers:
10) y= 1/2x - 2
11) y= 2x + 3
12) y= 2/3x - 4
I found this by using y=mx+ b
A. one solution
B 4(2x-5) = 4
2x-5 = 1
2x = 6
x=3