The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.
<h3>Define the term (distribution) transparency?</h3>
Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.
- The DDBMS designer has the option of replicating table fragments, storing them at several locations, and fragmenting tables.
- There are numerous distribution methods. Systems that need a wide range of management systems to pinpoint the source of resources, a product, or a service delivery process from the end user.
- Typically, the distributor, seller, or producer is responsible for maintaining transparency to track the many points at which resources, goods, or services are delivered.
- Accounting supplied by any intermediary company in the product, service, or resource flow is, of course, the usual approach to determine the degrees of value added through distribution management.
Thus, access transparency, location transparency are some examples of the (distribution) transparency.
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Answer:
D)
Step-by-step explanation:
ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END
OF 15.34 MEANS [DENOTING MEAN BY M AND Standard Deviation. BY S]
M±AS=20%....................M-AS=15.34
FOR 20% LEVEL .......A=1.281........FROM TABLES
M-1.281×S=15.34............................1
SIMILARLY
M±BS=40%...................M+BS=16.31
FOR 40% LEVEL .............B=0.841...................FROM TABLES
M+0.841×S=16.31.............................2
EQN.2 - EQN.1
2.122×S=0.97
S=0.457=0.46
M=15.926= 15.93
HENCE, D IS THE ANSWER
that is D. μ = 15.93, σ =.46
Answer:
$6.20 is the cost of candy per pound.
5/31 lbs of candy would be for $1.
Step-by-step explanation:
Rounded to the nearest tenth the number doesn't change Fam <span />
Answer:
Step-by-step explanation:
Given is a triangle RST and another triangle R'S'T' tranformed from RST
Vertices of RST are (0, 0), (negative 2, 3), (negative 3, 1).
Vertices of R'S'T' are (2, 0), (0, negative 3), (negative 1, negative 1).
Comparing the corresponding vertices we find that x coordinate increased by 2 while y coordinate got the different sign.
This indicates that there is both reflection and transformation horizontally to the right by 2 units
So first shifted right by 2 units so that vertices became
(2,0) (0,3) (-1,1)
Now reflected on the line y=0 i.e. x axis
New vertices are
(2,0) (0,-3) (-1,-1)