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3 years ago

Someone please help this is for a grade but I forgot how to do this helppp!!

Mathematics

1 answer:

shepuryov [24]3 years ago

8 0

First problem: 24/3=8
24 km irl is 8 cm on the map

problem #2: 9 times 17 = 153
The cities are 153 miles apart

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Divide. Give the quotient and remainder 18divided by 4

blagie [28]

Answer:

4 with a remainder of 2.

Step-by-step explanation:

5 0

2 years ago

The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. find the diameter of the base of the cylinder

White raven [17]

Answer:

2 cm

Step-by-step explanation:

h = 14 cm

Curved surface area of a right circular cylinder = 88 cm²

2πrh = 88

$2 * \frac{22}{7}*r*14=88\\\\r = \frac{88*7}{2*22*14}\\\\ r =1 \\\\r = 1 cm$

Diameter = 2 * r = 2 * 1 = 2 cm

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3 years ago

What is the y-intercept of a line that has a Slope of 3 and passes through point (-1, -7)

Degger [83]

Answer:

B)-4

Step-by-step explanation:

y=mx+c

sub in a point and gradient/slope to get c

-7=3(-1)+c

-7=-3+c

-7+3=c

c=-4

y=3x-4

if u looking for the y intercept make x=0

y=3(0)-4

y=-4

6 0

2 years ago

Read 2 more answers

Write the recurring decimal 0.4 as a fraction in its simplest form.

Ugo [173]

Answer:

2/5

Step-by-step explanation:

0.4 = 4/10 which in simplest form is 2/5

8 0

2 years ago

Read 2 more answers

A certain CD-ROM disk can store approximately 6.0 × 102 megabytes of information, where 106 bytes = 1 megabyte. If an average wo

klemol [59]

Answer: A. $4.3\times10^7$

Step-by-step explanation:

Given : A certain CD-ROM disk can store approximately $6.0 \times 10^2$ megabytes of information.

1 megabyte = $10^6$ bytes

Then, The storage capacity of CD-ROM disk will be :

$10^6\times 6.0 \times 10^2=6\times10^{6+2}=6\times10^8$

If an average word requires 14 bytes of storage, then the number of words can be stored :-

$\dfrac{6\times10^8}{14}=0.428571428571\times10^8\approx0.43\times10^8=4.3\times10^7$

Hence, number of words can be stored = $4.3\times10^7$

4 0

3 years ago