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emmasim [6.3K]
4 years ago
10

The diameter of a circle is 6 meters what’s is the circles area

Mathematics
2 answers:
elena55 [62]4 years ago
3 0

Answer:

A≈28.27m²

d Diameter

6

faust18 [17]4 years ago
3 0

Answer:

A≈28.27m²

d Diameter

6

Step-by-step explanation:

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7 0
3 years ago
Solve for x: 3(x + 1) = −2(x − 1) − 4.
Vlad [161]

Answer:

Multiply the first bracket by 3

Multiply the second bracket by -2

3x+3=-2x+2-4

3x+2x+3=-2x-2   negative (-) number and positive number (+)= negative number

Just rearranging

5x+3=-2

5x+3-3=-2-3

5x=-5

Dividing by 5

5x/5=-5/5

x=-1

Check answer by using substitution method

3(-1+1)=-2(-1-1)-4

0=-2(-2)-4 negative number and negative number = positive number

0=4-4

0=0

Answer is x=-1

6 0
4 years ago
You share a coin collection with a friend. You possess 44 of the coins and
vfiekz [6]

Answer:

Step-by-step explanation:

6 0
3 years ago
Four lawn sprinkler heads are fed by a 1.9-cm-diameter pipe. The water comes out of the heads at an angle of 35° above the horiz
klemol [59]

Answer:

Step-by-step explanation:

Given:

Angle, θ = 35°

Vertical distance, Δx = 6 m

Diameter, d = 1.9 cm

= 0.019 m

A.

When the water leaves the sprinkler, it does so at a projectile motion.

Therefore,

Using equation of motion,

(t × Vox) = 2Vo²(sin θ × cos θ)/g

= Δx = 2Vo²(sin 35 × cos 35)/g

Vo² = (6 × 9.8)/(2 × sin 35 × cos 35)

= 62.57

Vo = 7.91 m/s

B.

Area of sprinkler, As = πD²/4

Diameter, D = 3 × 10^-3 m

As = π × (3 × 10^-3)²/4

= 7.069 × 10^-6 m²

V_ = volume rate of the sprinkler

= area, As × velocity, Vo

= (7.069 × 10^-6) × 7.91

= 5.59 × 10^-5 m³/s

Remember,

1 m³ = 1000 liters

= 5.59 × 10^-5 m³/s × 1000 liters/1 m³

= 5.59 × 10^-2 liters/s

= 0.0559 liters/s.

For the 4 sprinklers,

The rate at which volume is flowing in the 4 sprinklers = 4 × 0.0559

= 0.224 liters/s

C.

Area of 1.9 cm pipe, Ap = πD²/4

= π × (0.019)²/4

= 2.84 × 10^-4 m²

Volumetric flowrate of the four sprinklers = 4 × 5.59 × 10^-5 m³/s

= 2.24 × 10^-4 m³/s

Velocity of the water, Vw = volumetric flowrate/area

= 2.24 × 10^-4/2.84 × 10^-4

= 0.787 m/s

7 0
4 years ago
Read 2 more answers
62. Height Kirsten places her surveyor's telescope on the top of
Solnce55 [7]

Answer:

21 feet

Step-by-step explanation:

Given :

Height of the tripod above the ground = 5 ft

Elevation = 8°

Distance of the tree from the tripod = 120 ft

Therefore from the figure, we can find the height of the tress as:

$\tan 8 ^\circ = \frac{BC}{AB}$

$0.1405  = \frac{BC}{120}$

∴  BC ≈ 16

Therefore, CE = BC+BE

                        = 16 + 5

                        = 21

Therefore the height of the tree is 21 feet.

4 0
3 years ago
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