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olga nikolaevna [1]
2 years ago
9

What 7/16 + 9/16 equal to.

Mathematics
2 answers:
Diano4ka-milaya [45]2 years ago
8 0
Hi,

Equation;

\frac{7}{16}  +  \frac{9}{16}   =  \frac{16}{16}  = 1

Hope this helps.
r3t40
marusya05 [52]2 years ago
4 0
7 sixtieths + 9 sixtieths = 16 sixtieths

So we have 16 of 1/16 = 1 whole
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Answer:

the answer is b

Step-by-step explanation:

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niah works as a retail sales clerk earning $18,000 per yer. she plans to go to school for medical billing that has a median sala
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Investment: cost of her education + salary as sales clerk during two years

Investment = 18,000 (2) + 20,000 = 36,000 + 20,000 = 56,000

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3 0
3 years ago
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2. The ratio of boys to girls in the school
andrew11 [14]
Since the ratio is 3:4, and 12/4 is 3 than you do 3x3 and get 9 so the answer is 9:12 or 9 boys and 12 girls. To check your answer, you can do 3/4 (for 3:4) and that is 0.75. If you do that with 9:12 you also get 0.75.
5 0
2 years ago
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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0
3 years ago
Write an exponential function in the form y=ab^xy=ab x that goes through points (0, 20)(0,20) and (6, 1280)(6,1280).
Phoenix [80]

Answer:

y=20(2)^x

Step-by-step explanation:

We want to write an exponential function that goes through the points (0, 20) and (6, 1280).

The standard exponential function is given by:

y=ab^x

The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:

20=a(b)^0

Simplify:

20=a(1)\Rightarrow a=20

So, our exponential function is now:

y=20(b)^x

Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:

1280=20(b)^6

Solve for <em>b</em>. Divide both sides by 20:

64=b^6

Therefore:

b=\sqrt[6]{64}=2

Hence, our function is:

y=20(2)^x

8 0
2 years ago
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