Answer:
The average speed on the return trip is 2.44 miles/h.
Step-by-step explanation:
To find the average speed we need to use the following equation:
Where:
d: is the distance
t: is the time
Since the question is to find the average speed on the return trip, we will take the data of the time and speed of only the return trip.
Therefore, the average speed on the return trip is 2.44 miles/h.
I hope it helps you!
Answer:
-19/132
Step-by-step explanation:
To add fractions, find the lowest common multiple of the two denominators and multiply accordingly to make both denominators the same. In this case, the lowest common multiple of 11 and 12 is 132, so we need to multiply the first number by 12 and the second by 11. So we get =
=
The two dot plots are missing, so i have attached it.
Answer:
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Step-by-step explanation:
From the attached image, we are told to compare the means for each plot to the nearest tenth.
Mean = Σx/n
Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;
(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133
Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles
Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143
Mean of miles run at the end of the school year = 143/14 = 10.2 miles
Thus;
The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles
Answer:
Step-by-step explanation:
To aid in understanding, draw three circles...
100 were registered for both Math and English.
50 were registered for both Sport and English but not Math.
70 were registered for Math, Sport, and English.
From here we will be able to calculate for those that signed up for only English class: Total number of students that signed up for english class
a. none signed up only for Maths (refer to attached document)
b. How many signed up for neither Math nor English meaning they signed up for only sports which is 70 from the venn diagram in the attachment.
c. How many signed up for an English class and at least one other class?
From the venn diagram:
we could have an English class and maths class - 100
we could also have an a English class and sports - 50
Thus total is 150.
d. What is the total fee for all the students enrolled in classes
From the diagram, 120 (english only and sport only) enrolled for only one class = 120 x $100 = $12,000
From the diagram, 180 (english and sport, maths and sport and english and maths) enrolled for two classes = 180 x $150 = $27,000
From the diagram, only 70 enrolled for the three classes = 70 x $200 = $14,000
Total fees = $12,000 + $27,000 + $14,000 = $53,000
