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Mazyrski [523]
3 years ago
5

John took a 5 1/2 mile walk to his friend's house. He left at 11 a.M. And arrived at his friend's house at 12:45 p.M. Therefore

it took him 1 3/4 hours to get to his friends house. If the return trip took 2 1/4 hours, what is the average speed on the return trip?
Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer:

The average speed on the return trip is 2.44 miles/h.                  

Step-by-step explanation:

To find the average speed we need to use the following equation:

\overline{v} = \frac{d}{t}

Where:

d: is the distance

t: is the time

Since the question is to find the average speed on the return trip, we will take the data of the time and speed of only the return trip.

\overline{v} = \frac{d}{t} = \frac{5 + 1/2}{2 + 1/4} = 2.44 miles/h                

Therefore, the average speed on the return trip is 2.44 miles/h.

I hope it helps you!

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