Question

John took a 5 1/2 mile walk to his friend's house. He left at 11 a.M. And arrived at his friend's house at 12:45 p.M. Therefore it took him 1 3/4 hours to get to his friends house. If the return trip took 2 1/4 hours, what is the average speed on the return trip?

Answer 1

Answer:

The average speed on the return trip is 2.44 miles/h.                  

Step-by-step explanation:

To find the average speed we need to use the following equation:

$\overline{v} = \frac{d}{t}$

Where:

d: is the distance

t: is the time

Since the question is to find the average speed on the return trip, we will take the data of the time and speed of only the return trip.

$\overline{v} = \frac{d}{t} = \frac{5 + 1/2}{2 + 1/4} = 2.44 miles/h$                

Therefore, the average speed on the return trip is 2.44 miles/h.

I hope it helps you!