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solong [7]
3 years ago
5

Eric sheena and heal are playing a game Eric has half as many points as sheena sheena has theee fewer points than Yael together

the three players have 68 points how many points does yael have
Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer

68

Step-by-step explanation:

I think

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The sum of 3 consecutive even integers is 78. What is the largest of the integers?
Maksim231197 [3]

Answer:

is the sum 78 or 7,878 (i.e. was there a stutter)?

In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.

Set that to either 78 or 7878, whichever is intended, & solve for n.   If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.

No stress!  Just logic! Keep the faith!

Step-by-step explanation:

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3 years ago
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What is the result when the number 4 is decreased by 25%?
OleMash [197]
4/4=1. So we need to subtract 1 from 4 to get the final Answer which is 3.
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3 years ago
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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
LiRa [457]

Answer:

x = 7, -7

Step-by-step explanation:

(2x-1)(3x+2)+x+292

3x - 2x +x = 2 - 1 + 292

(6)x - 294 = 6(x - 49)

Use communicative property of multiplication

Example: (A+B)(A-B)

Ax^{2} -AB+BA-Bx^{2} =Ax^{2} -AB+AB-Bx^{2} =\\Ax^{2} -Bx^{2}

49 is the square of 7

x square is the square of x to the power of 1

(x+7)(x-7)

5 0
3 years ago
Show that the points (0.-1).(2, 1).(0.3) and (-2, 1) are the vertices of a square ABCD.
Inessa05 [86]

The diagram is below

  • A = (0,-1)
  • B = (2,1)
  • C = (0,3)
  • D = (-2,1)

Let's find the distance from A to B using the distance formula.

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(0-2)^2 + (-1-1)^2}\\\\d = \sqrt{(-2)^2 + (-2)^2}\\\\d = \sqrt{4 + 4}\\\\d = \sqrt{8}\\\\d \approx 2.828\\\\

The distance from A to B is exactly \sqrt{8} units or approximately 2.828 units. This is the length of side AB.

Through very similar steps, you should find that the other side lengths of BC, CD and AD are all the same.

Since AB = BC = CD = AD, this means we have a rhombus. Recall a rhombus is any quadrilateral with all four sides the same length.

-----------------------------

Let's find the slope of line AB

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{1 - (-1)}{2 - 0}\\\\m = \frac{1 + 1}{2 - 0}\\\\m = \frac{2}{2}\\\\m = 1\\\\

Line AB has a slope of 1.

Through similar steps, you should find the slope of line BC is -1.

Rule: Whenever two slopes multiply to -1, then their corresponding lines are perpendicular.

Based on that rule, lines AB and BC are perpendicular. This means they meet up at a right angle (aka 90 degree angle).

You should find that line CD has a slope of 1, so BC and CD are perpendicular. Lastly, line AD has a slope of -1. So all the slopes mentioned are either +1 or -1. The slopes alternate as you move around the figure. This all shows that any two adjacent sides meet at a 90 degree angle.

Therefore, this figure is a rectangle. Any rectangle has all four angles of 90 degrees.

-----------------------------

The first section showed that we have a rhombus. The second section afterward showed that we also have a rectangle. The combination of a rhombus and a rectangle at the same time leads to a square.

Therefore, quadrilateral ABCD is a square.

5 0
3 years ago
WILL MARK BRAINLIEST ASAP!!
7nadin3 [17]

\dfrac{x^2+ax-4}{x+2}+\dfrac{x+b}{x+2}=\dfrac{x^2+ax-4+x+b}{x+2}=\dfrac{x^2+(a+1)x+(b-4)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=x+1\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x+1)(x+2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x)(x)+(x)(2)+(1)(x)+(1)(2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+2x+x+2}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+3x+2}{x+2}\iff a+1=3\ \wedge\ b-4=2\\\\\boxed{a=2\ \wedge\ b=6}

3 0
3 years ago
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