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mote1985 [20]
3 years ago
11

g A probability experiment is conducted in which the sample space of the experiment is Upper S equals StartSet 9 comma 10 comma

11 comma 12 comma 13 comma 14 comma 15 comma 16 comma 17 comma 18 comma 19 comma 20 EndSet . Let event Upper E equals StartSet 10 comma 11 comma 12 comma 13 comma 14 comma 15 comma 16 comma 17 EndSet . Assume each outcome is equally likely. List the outcomes in Upper E Superscript c . Find Upper P (Upper E Superscript c ).
Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

P(E^c)=\dfrac{1}{3}

Step-by-step explanation:

The sample space for the experiment  is:

S=\{9,10,11,12,13,14,15,16,17,18,19,20\}

  • Number of elements in S, n(S)=12

Given an event E such that:

E=\{10,11,12,13,14,15,16,17\}

  • Number of elements in E, n(E)=8

The outcomes in the complement of E are the outcomes in S that are not in E.

E^c=\{9,18,19,20\}

  • Number of elements in the complement of E, n(E^c)=4

Therefore:

P(E^c)=\dfrac{n(E^c)}{n(S)}\\ =\dfrac{4}{12}\\P(E^c)=\dfrac{1}{3}

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