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Blizzard [7]
3 years ago
14

Lee el anexo , posteriormente Escribe 5 preguntas en su cuaderno referente al texto que leiste.

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

Las cinco preguntas extraídas del anexo se encuentran a continuación:

  1. ¿Cuál es le nombre del virus que provoca la enfermedad llamada coronavirus?
  2. ¿Los síntomas de coronavirus son graves en todas las personas?
  3. ¿Cómo se propaga el coronavirus?
  4. ¿Cómo se puede contagiar del virus una persona?
  5. Para disminuir el riesgo de contagio, ¿es mejor permanecer en espacios cerrados o en espacios abiertos? ¿Por qué?

<em>Extracción</em><em> de </em><em>preguntas</em><em> a partir de un texto</em>.

Cuando se requiere elaborar preguntas, a partir de un texto predeterminado, es ideal que primero se lea el texto y se identifiquen todos los temas y subtemas que este contiene, así, con cada uno de estos, se podrán realizar preguntas, garantizando que la totalidad de la respuesta se encuentre dentro del texto, ya sea de forma explícita o implícita, este último caso cuando la persona debe inferir algunas especificaciones con la información brindada.

Si quieres aprender un poco más sobre el coronavirus, puedes visitar el siguiente enlace: brainly.com/question/22435929?referrer=searchResults

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43. Ricardo just received a shipment of 50 tool sheds for his garden supply store. Each shed costs him $40. Which of the followi
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Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
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Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

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What is the are of the figure below​
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