B. congruent, im pretty sure
Evet canım benim için çok teşekkür ederimmm
Answer:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers
and
.
To check whether
is an integer:
Condition (1):
Every factor of
is also a factor of
.

Let us consider an example:

which is an integer.
Actually, in this situation
is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let


which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Answer:

Step-by-step explanation:
log20 = 1.301 (when you see only "log" with no base, it is taken as a base 10)
This basically means:
(This is the log in exponential form)
Since we don't know what
is equal to, we will say
= x
So to solve for
= x, you do the same thing. (convert to exponential form)

Now you will notice that both of these equations are equal to 20.
Since 20 = 20,
we can say
= 
Another way of saying 100, is
(make the bases the same)
Now we get
(we get 2x because an exponent to the power of an exponent (
) is the same as 2 * x)
Because you have the same base, you can just ignore the 10s and focus on the exponents. So you get:
2x = 1.301
x = 0.6505