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RUDIKE [14]
2 years ago
8

Find the x- and y-intercepts of the graph of the linear equation −4x+8y=−16.

Mathematics
1 answer:
Bogdan [553]2 years ago
8 0
Put it in slope form: y=mx+b
8y= 4x-16
Divide by 8
Y = 1/2x -2
1/2 is x intercept and -2 is y intercept
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Help me with this math work please
Aloiza [94]
Your photo is super blurry! I can’t read parts of the problems, so I can’t exactly help you. Sorry! Good luck.
7 0
2 years ago
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Find the equation in standard form of the line passing through the points 3,-4 and 5,1
aliina [53]

Answer:

5x - 2y - 23 = 0

Step-by-step explanation:

Line is passing through the points (3,\:-4)= (x_1, \:y_1) \: \&\: (5,\: 1)= (x_2,\:y_2)

Equation of line in two point form is given as:

\frac{y -y_1 }{y_1 -y_2 }  =  \frac{x -x_1 }{x_1 -x_2 } \\  \\  \therefore \:  \frac{y -( - 4) }{ - 4 -1}  =  \frac{x -3 }{3 -5 } \\  \\  \therefore \:\frac{y  +  4 }{ - 5}  =  \frac{x -3 }{ - 2 } \\  \\  \therefore \: \frac{y  +  4 }{  5}  =  \frac{x -3 }{  2 } \\  \\  \therefore \:  2(y + 4) = 5(x - 3) \\ \therefore \:  2y + 8 = 5x - 15 \\ \therefore \: 5x - 15 - 2y - 8 = 0 \\  \red{ \boxed{ \bold{\therefore \: 5x - 2y - 23 = 0}}} \\ is \: the \: required \: equation \: of \: line \: in \:  \\ standard \: form.

7 0
3 years ago
A cleaning product sells for $0.75 a quart. Which equation can be used to solve for the total cost, C , of five gallons of the p
ozzi

Answer: b. C = 5 × ($0.75 × 4)

Step-by-step explanation:

Note that 4 quarts = 1 gallon

Therefore, if a cleaning product sells for $0.75 a quart, the equation can be used to solve for the total cost, C , of five gallons of the product will be:

= 5 × ($0.75 × 4)

= 5 × $3

= $15

8 0
2 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
Solve for x 5 – 57− 2 = 63 please help
umka2103 [35]
5x - 2x = 63 + 57
3x = 120
x = 40
4 0
3 years ago
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