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Shkiper50 [21]
3 years ago
7

A new car worth 25,000 is depreciating(loses value) in value by 1,250 per year. Determine how many years will it take for the ca

r to be worth 8,500
Mathematics
1 answer:
Svet_ta [14]3 years ago
8 0
The value x years from now will be
   v(x) = 25000 - 1250x

Filling in the given information, we have
   8500 = 25000 - 1250x
   8500 - 25000 = -1250x
   -16500/-1250 = x = 13.2

It will take 13.2 years for the car to be worth 8,500.
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Answer: Yes, 11 refridgerators and 9 pianos will overload the truck because 11x300=3,300 and 9x425=3,825 which in total equals 7,125, which is way too much for the truck.

An equation that works: 300(10)+425(8)=

Step-by-step explanation:

If each refrigerator is 300 pounds and we need to see if 11 would fit on the truck, multiply 300 times 11 which equals 3,300. Next repeat the same step but for the pianos… 425 times 9 which equals 3,825 now you add. You should get 7,125, meaning this ratio is way to large for the truck to carry.

Since this does not work we should try take away one of each. So let’s say the new rati is 10 refrigerators to 8 pianos. We would repeat the same steps from above. 10x300=3,000       8x425=3,400

If we add these, we get 6,400 so the final expression would be 300(10)+425(8)=6,400 which would be the closest the the most you can transport on the truck.

Sorry if this was not the answer you were looking for, I may have misinterpreted the question.

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