Answer:
121
Step-by-step explanation:
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<u>Answer:</u>
The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
<u>Solution:</u>
Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)
We have to find the line equation which is perpendicular to above given line and passing through the given point.
Now, let us find the slope of the given line equation.

We know that, <em>product of slopes of perpendicular lines is -1.
</em>
So, 1
slope of perpendicular line = -1
slope of perpendicular line = -1
Now let us write point slope form for our required line.

y – (-2) = -1(x – (-3))
y + 2 = -1(x + 3)
y + 2 = -x – 3
x + y + 2 + 3 = 0
x + y + 5 = 0
y = -x -5
Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.
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Answer with Step-by-step explanation:
We are given that an equation of curve

We have to find the equation of tangent line to the given curve at point 
By using implicit differentiation, differentiate w.r.t x
Using formula :



Substitute the value x=
Then, we get


Slope of tangent=m=
Equation of tangent line with slope m and passing through the point
is given by

Substitute the values then we get
The equation of tangent line is given by




This is required equation of tangent line to the given curve at given point.