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3 years ago

28 + 8x = 8(x + 3) + 2What is x?

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

3 0

Answer:

Step-by-step explanation:

28 + 8x = 8x + 24 + 2

28 + 8x = 8x + 26

28 ≠ 26

no solution

lianna [129]3 years ago

3 0

Answer:

The equation is invalid.

Step-by-step explanation:

Simplifying:

28 + 8x = 8(x + 3) + 2

Reorder the terms:

28 + 8x = 8(3 + x) + 2

28 + 8x = (3 * 8 + x * 8) + 2

28 + 8x = (24 + 8x) + 2

Reorder the terms:

28 + 8x = 24 + 2 + 8x

Combine like terms: 24 + 2 = 26

28 + 8x = 26 + 8x

Add '-8x' to each side of the equation.

28 + 8x + -8x = 26 + 8x + -8x

Combine like terms: 8x + -8x = 0

28 + 0 = 26 + 8x + -8x

28 = 26 + 8x + -8x

Combine like terms: 8x + -8x = 0

28 = 26 + 0

28 = 26

Solving:

28 = 26

The left and right sides are not equal! Meaning theres no solution.

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3 years ago

5 - 6 - 9 - 8 - 5 - 4 + 5 - 5 -5 -5 - 32 = ?

musickatia [10]

5 - 6 = -1

-1 - 9 = -10

-10 - 8 = -18

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2 years ago

Read 2 more answers

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vazorg [7]

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3 years ago

If cos(θ)=2853 with θin Q IV, what is sin(θ)?

marysya [2.9K]

Answer: $\sin \theta=\frac{-45}{53}$

Step-by-step explanation:

Since we have given that

$\cos\theta=\frac{28}{53}$

And we know that θ is in the Fourth Quadrant.

So, Except cosθ and sec θ, all trigonometric ratios will be negative.

As we know the "Trigonometric Identity":

$\cos^2\theta+\sin^2\theta=1\\\\\sin \theta=\sqrt{1-\cos^2\theta}\\\\\sin \theta=\sqrt{1-(\frac{28}{53})^2}=\sqrt{\frac{53^2-28^2}{53^2}}\\\\\sin \theta=\sqrt{\frac{2025}{53^2}}\\\\\sin \theta=\frac{45}{53}$

It must be negative due to its presence in Fourth quadrant.

Hence, $\sin \theta=\frac{-45}{53}$

7 0

3 years ago

28 + 8x = 8(x + 3) + 2What is x? ​

28 + 8x = 8(x + 3) + 2What is x?