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nlexa [21]
3 years ago
8

The point is on the x-axis and 12 units to the left of the y-axis.

Mathematics
1 answer:
tekilochka [14]3 years ago
7 0

Check the picture below.

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Find the quotient of 21x^2y^6+6xy^3-30xy/3xy.
kaheart [24]
\bf ~~~~~~~~~~~~\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
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\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------

\bf \cfrac{21x^2y^6+6xy^3-30xy}{3xy}\implies \stackrel{\textit{distributing the denominator}}{\cfrac{21x^2y^6}{3xy}+\cfrac{6xy^3}{3xy}-\cfrac{30xy}{3xy}}
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\cfrac{21}{3}\cdot x^2x^{-1}y^6y^{-1}+\cfrac{6}{3}\cdot x^1x^{-1}y^3y^{-1}-\cfrac{30}{3}\cdot x^1x^{-1}y^1y^{-1}
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7x^{2-1}y^{6-1}+2x^{1-1}y^{3-1}-10x^{1-1}y^{1-1}\implies 7xy^5+2y^2-10
3 0
3 years ago
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The cost of renting a pickup truck at Trucks Plus is $25 plus $15 cents per mile driven. The cost of renting a truck at Need-A-T
kodGreya [7K]
Okay so. Here's what it looks like :    TRUCK PLUS: $25 is the fee upfront. so no matter what your GOING to pay $25 for using the company. Next 15 cents for every mile driven. So if the truck were to drive 3 miles it would be $.45 cents

NEED-A-TRUCK : Same thing. You have to pay $25 no matter what. But for this company you have to pay $.10 per mile.  COST PER MILE means that basically the more miles you drive, the more cents you have to pay. Does that make sense? <span />
6 0
3 years ago
John made this model to show \frac{4}{7}\times\frac{13}{9} 7 4 ​ × 9 13 ​ Using John's model, what is \frac{4}{7}\times\frac{13}
harkovskaia [24]

Answer:

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

Step-by-step explanation:

Given

See attachment for model

Required

Determine \frac{4}{7}\times\frac{13}{9} from the model

The model is represented by:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 36 ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{9}{9} = \frac{36}{63}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 16 (do not count the gray boxes) ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{4}{9} =\frac{16}{63}

The equation becomes:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

\frac{4}{7}\times\frac{13}{9} = \frac{36}{63} + \frac{16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{36+16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

5 0
3 years ago
Expand ( x - 1/x^2)^4
emmainna [20.7K]

Answer:

We want to expand the expression:

(x - \frac{1}{x^2} )^4

We can just do it by brute force, this is:

First, rewrite our expression as the product of two square factors:

(x - \frac{1}{x^2} )^4 = (x - \frac{1}{x^2} )^2*(x - \frac{1}{x^2} )^2

Now we can expand each one these two factors:

(x - \frac{1}{x^2} )^2 = (x - \frac{1}{x^2} )*(x - \frac{1}{x^2} ) = x^2 + \frac{1}{x^4} -2*x*\frac{1}{x^2}

That can be simplified to

x^2 - \frac{2}{x} + \frac{1}{x^4}

Now we can replace that in our original expression to get:

(x^2 - \frac{2}{x} + \frac{1}{x^4})*(x^2 - \frac{2}{x} + \frac{1}{x^4})

Now we can expand that last product, to get:

(x^2)^2 + 2*(x^2)*(-\frac{2}{x} ) + 2*(x^2)*(\frac{1}{x^4}) + 2*(\frac{-2}{x})*(\frac{1}{x^4}) + (\frac{-2}{x}  )^2 + (\frac{1}{x^4})^2

We can simplify that to:

x^4 - 4x + 2x^2 - \frac{4}{x^5}  + \frac{4}{x^2} + \frac{1}{x^8}

That is the expanded expression.

6 0
2 years ago
Please tell me the answer! I'm crying in confusion! :(
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7G: m<Q=150

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