Question

Please help me!! will mark you brainliast

Answer 1

Answer: $x=7 sqrt(6)\ \ or\ x=7\sqrt{6}$

Step-by-step explanation:

For this exercise you can use the following Trigonometric Identity:

$sin\alpha =\frac{opposite}{hypotenuse}$

In this case you can identify in the figure given in the exercise that:

$\alpha =45\°\\\\opposite=7\sqrt{3}\\\\hypotenuse=x$

Knowing those values, you must substitute them into  $sin\alpha =\frac{opposite}{hypotenuse}$, as following:

$sin(45\°)=\frac{7\sqrt{3}}{x}$

Now you must solve for "x" in order to find its value.

You need to remember that, by definition:

 $sin(45\°)=\frac{1}{\sqrt{2}}$

Therefore, you get that the value of "x" is:

$(x)(\frac{1}{\sqrt{2}} )=7\sqrt{3}\\\\x=(7\sqrt{3})( \sqrt{2}})\\\\x=7\sqrt{6}}$