<u>Answer:</u>
The statement, Maya’s expression will generate the correct sum because of the associative property will describe the best.
<u>Solution: </u>
Maya’s expression will generate the correct sum because of the associative property.
Maya wrote the expression
As per commutative property of addition if we change the order still the sum will be same, which means
Here also,
Again
As both the results are same, hence this is meeting the commutative property of addition.
Answer:
1. The volume of the cylinder is approximately 0.153 m³
2. 25 cm
3.
4. 16 m
5. 1,785 m³
Step-by-step explanation:
The volume of a solid can be found by the product of the uniform cross-sectional area of the solid and the (continuous) length of the solid
1. The uniform cross-sectional area of the given cylinder = The area of the circle at the base or top
The dimension of the diameter of the circle at the top of the cylinder, d = 50 cm = 0.5 m
The area of the circular cross-section, A = π·d²/4
∴ A = π × 0.5²/4 = 0.0625·π
A = 0.0625·π m²
The height of the cylinder, h = The continuous length of the circular cross-section = 78 cm = 0.78 m
∴ The volume of the cylinder, V = A × h
∴ V = 0.0625·π × 0.78 = 0.04875·π ≈ 0.153
The volume of the cylinder, V ≈ 0.153 m³
2. The given volume of the trapezium, V = 8550 cm³
The length of the short and long parallel sides 'a', and 'b', are 17 cm and 21 cm respectively
The height of the trapezium from the diagram, h = 18 cm
The cross-sectional area of the trapezium, 'A', is found as follows;
A = (17 cm + 21 cm)/2 × 18 cm = 342 cm²
The volume of the trapezium, V = The cross-sectional, A × The (missing) length, 'l' of the trapezium
∴ l = V/A
By substitution, we have;
l = 8550 cm³/(342 cm²) = 25 cm
∴ The Missing Length, l = 25 cm
3. The given volume of the solid having a uniform cross-sectional area is, V = 385 cm³
The area of the (uniform) cross-section of the solid, A = 15 cm²
∴ The length of the solid, 'l', from V = A × l, is given as follows;
l = V/A
∴ l = 385 cm³/(15 cm²) = 25. cm
The length of the solid, l = 25. cm
4. From the diagram, we have;
The cross-sectional area of the solid, A = 216 m²
The length of the solid, l = 16 m
5. The cross-section of the solid can can be assumed to be either;
1. A trapezium from which a rectangle has been removed of dimensions 8 m by 9 m.
2. A triangle located above a rectangle
For scenario one, we have;
The cross-sectional area, A = (12.5 + 9)/2 × 15 - 8 × 9 = 89.25
For scenario two, we find 'A' as follows;
A = 7 × 9 + 1/2 × 15 × 3.5 = 89.25
∴ The cross-sectional area of the solid, A = 89.25 m²
The length, 'l', of the solid, is given as l = 20 m
The volume of the solid, V = A × l
∴ V = 89.25 m² × 20 m = 1,785 m³
The volume of the solid, V = 1,785 m³.