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FromTheMoon [43]
3 years ago
12

Find the polynomial. (2y − 9)(2y − 9) is the factored form of the expression .

Mathematics
2 answers:
Roman55 [17]3 years ago
7 0
(2y-9)(2y-9)
(2y-9)^2
(2y)^2-2*2y*9+9^2
4y^2-36y+81

ehidna [41]3 years ago
7 0

Answer:

The polynomial whose factored form is  (2y-9)(2y- 9)

is  4y^2+81-36y

Step-by-step explanation:

Given : Factored form of a polynomial as (2y-9)(2y- 9)

We have to find the polynomial whose factored form is  (2y-9)(2y- 9)

Consider the given expression  (2y-9)(2y- 9)

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

We have,

\left(2y-9\right)\left(2y-9\right)=\:\left(2y-9\right)^{1+1}=\:\left(2y-9\right)^2

Thus, Applying algebraic identity, (a-b)^2=a^2+b^2-2ab,  we have,

a = 2y and b = 9

Thus,  (2y-9)^2=(2y)^2+9^2-2\cdot 2y \cdot 9

Simplify, we have,

(2y-9)^2=4y^2+81-36y

Thus, The polynomial whose factored form is  (2y-9)(2y- 9)

is  4y^2+81-36y

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Answer:

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Step-by-step explanation:

Set each factor equal to 0 and solve

2x + 4 =0

2x = -4

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3 years ago
Which statements are true about the median of a data set? Check all that apply. The median isn’t affected much by one outlier. T
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These are all the right answers:

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Hope this helped :)
7 0
3 years ago
Read 2 more answers
5.<br>Find the sum of all two - digit natural numbers which are divisible by 3.​
kykrilka [37]

Answer:

1665

Step-by-step explanation:

This is AP, where:

  • First term is: 12= 3*4
  • Last term is: 99= 3*33
  • Common difference is: 3
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The sum of all two - digit natural numbers which are divisible by 3 is 1665

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