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3 years ago

(-0.3) + 0.9 find the sum

Mathematics

2 answers:

lesya692 [45]3 years ago

7 0

The answer is 0.6 how it helped

IceJOKER [234]3 years ago

3 0

Answer: (-0.3) + 0.9= 0.6

Step-by-step explanation:

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Mr. Naxvip wrote the expression below to represent the number of

aliya0001 [1]

Answer:

Step-by-step explanation:

b×3+5-1

=5×3+5-1

= 19

4 0

3 years ago

Find domain of the rational function C(x)=-x-5/x^2-25

iren2701 [21]

$\large\begin{array}{l} \textsf{Find the domais of the rational function:}\\\\ \mathsf{C(x)=\dfrac{x-5}{x^2-25}}\\\\\\ \textsf{Denominators can't be zero:}\\\\ \mathsf{x^2-25\ne 0}\\\\ \mathsf{x^2\ne 25}\\\\ \begin{array}{rcl} \boxed{\begin{array}{rcl}\mathsf{x\ne -5}&~\textsf{ and }~&\mathsf{x\ne 5}\end{array}} \end{array} \end{array}$

$\large\begin{array}{l} \textsf{So the domain of C is}\\\\ \mathsf{D_C=\{x\in\mathbb{R}:~~x\ne -5~~and~~x\ne 5\}}\\\\\\ \textsf{or using a more compact form}\\\\ \mathsf{D_C=\mathbb{R}\setminus\{-5,\,5\}}\\\\\\ \textsf{or in interval notation}\\\\ \mathsf{D_C=\left]-\infty,\,-5\right[\,\cup\,\left]-5,\,5\right[\,\cup\,\left]5,\,+\infty\right[\,.} \end{array}$

$\large\textsf{So pick up the one you prefer. They're equivalent ways}\\\textsf{to represent the domain.}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2184171

$\large\textsf{I hope this helps. :-)}$

Tags: domain rational function fraction denominator restriction algebra

4 0

3 years ago

Help with this I don't know how to solve

Hunter-Best [27]

Answer:

86.53

Step-by-step explanation:

Area of Triangle Formula: A = 1/2bh

Pythagorean Theorem: a² + b² = c²

Step 1: Draw altitude and label numbers

If we draw a line down the middle, we can see that we get a perpendicular bisector and that we get 2 right triangles with a hypotenuse of 29 and a leg of 3. We need to find h using Pythagorean Theorem in order to use area formula:

3² + b² = 29²

b² = 29² - 3²

b = √832 = h

Step 2: Plug in known variables into area formula:

A = 1/2(√832)(6)

A = 3√832

A = 86.5332

7 0

3 years ago

Which of the values for x and y make the equation 2x + 3y + 4 = 15 true?

natima [27]

2(1)+3(3)+4=15
2+9+4=15
Or
2(4)+3(1)+4=15
8+3+4=15
So either one would work

7 0

3 years ago

The quantity demanded x each month of Russo Espresso Makers is 250 when the unit price p is $138. The quantity demanded each mon

Stells [14]

Answer:

(a) $D(q)=\frac{-1}{25} q+148$

(b) $S(q)=\frac{1}{50}q+58$

Step-by-step explanation:

(a) For the demand equation D(q) we have

P1: 138 Q1: 250

P2: 108 Q2: 1000

We can find m, which is the slope of the demand equation,

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{108-38}{1000-250} =\frac{-30}{750}=\frac{-1}{25}$

and then we find b, which is the point where the curve intersects the y axis.

We can do it by plugging one point and the slope into the line equation form:

$y=mx+b\\\\D(q)=mq+b\\\\138=\frac{-1}{25}(250) +b\\\\138=-10+b\\\\138+10=b=148$

With b: 148 and m: -1/25 we can write our demand equation D(q)

$D(q)=\frac{-1}{25} q+148$

(b) to find the supply equation S(q) we have

P1: 102 Q1: 2200

P2: 102 Q2: 700

Similarly we find m, and b

$m=\frac{p_{2} -p_{1} }{q_{2} -q_{1} }=\frac{72-102}{700-2200} =\frac{-30}{-1500}=\frac{1}{50}$

$y=mx+b\\\\D(q)=mq+b\\\\72=\frac{1}{50}(700) +b\\\\72=14+b\\\\72-14=b=58\\$

And we can write our Supply equation S(q):

$S(q)=\frac{1}{50}q+58$

(c) Now we may find the equilibrium quantity q* and the equilibrium price p* by writing D(q)=S(q), which means the demand equals the supply in equilibrium:

$D(q)=S(q)\\\\\frac{-1}{25}q+148=\frac{1}{50}q+58\\\\$

$148-58=\frac{1q}{50} +\frac{1q}{25} \\\\90= \frac{1q}{50} +\frac{2q}{50}\\\\90=\frac{3q}{50}\\ \\q=1500\\\\$

We plug 1500 as q into any equation, in this case S(q) and we get:

$S(q)=\frac{1}{50}q+58\\\\S(1500)=\frac{1}{50}(1500)+58\\\\S(1500)=30+58\\\\S(1500)=88$

Which is the equilibrium price p*.

8 0

3 years ago