Answer:
15
Step-by-step explanation:
Answer:
9/20
Step-by-step explanation:
Total trials = 80
Observed successful trials = 36
36/80
= 9/20
Answer:
36 possible class schedules
Step-by-step explanation:
1st - 4 ways
2nd - 3 ways
3rd - 3 ways
4 x 3 x 3 = 36 possible class schedules
The correct answer is: Option 3: 
Step-by-step explanation:
Given

We have to find

This will be equal to:

So we have to find the composition of (fog)(x) first

Now,

The correct answer is: Option 3: 
Keywords: Composition, Functions
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Using the greatest common factor, it is found that the greatest dimensions each tile can have is of 3 feet.
---------------------------
- The widths of the walls are of <u>27 feet, 18 feet and 30 feet.</u>
- <u>The tiles must fit the width of each wall</u>, thus, the greatest dimension they can have is the greatest common factor of 27, 18 and 30.
To find their greatest common factor, these numbers must be factored into prime factors simultaneously, that is, only being divided by numbers of which all three are divisible, thus:
27 - 18 - 30|3
9 - 6 - 10
No numbers by which all of 9, 6 and 10 are divisible, thus, gcf(27,18,30) = 3 and the greatest dimensions each tile can have is of 3 feet.
A similar problem is given at brainly.com/question/6032811