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3 years ago

PLS help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Darina [25.2K]3 years ago

5 0

9514 1404 393

Answer:

y = -1

Step-by-step explanation:

Sides marked with the same marking are congruent, so we have two equations:

3x -y = 16
2x +y = 9

Adding the equations gives ...

5x = 25

x = 5 . . . . . . divide by 5

Then the second equation tells us ...

y = 9 -2x = 9 -2(5) = -1

The value of y is -1.

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Use the position function s(t) = –4.9t2 + 500, which gives the height (in meters) of an object that has fallen for t seconds fro

weqwewe [10]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value is $v(3) = 29.4 \ m/s$

Step-by-step explanation:

From the question we are told that

$s(t) = -4.9t^2 + 500$

And

$\lim_{t \to a} \frac{s(a) - s(t)}{a-t}$

Generally s(t) at t = a is mathematically evaluated as

$s(a) = -4.9a^2+ 500$

$s(a) - s(t) = -4.9a^2 + 500 - ( -4.9t^2+500)$

$s(a) - s(t) = -4.9a^2 + 500 +4.9t^2-500)$

$s(a) - s(t) = 4.9(t^2 - a^2)$

Thus the velocity is represented as

$v(t) =\lim_{t \to a} \frac{s(a) - s(t)}{a-t} \equiv \lim_{t \to a} \frac{4.9(t^2 - a^2 )}{ a-t}$

=> $v(t) = \lim_{t \to a} - 4.9(a + t )$

=> $v(t) = -4.9 (a + a )$

=> $v(t) = -9.8a$

Now at t = 3

=> $v(3) = -9.8 (3)$

=> $v(3) = 29.4 \ m/s$

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Answer:

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