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3 years ago

7

More help please. I really would appreciate it!! :)

1 answer:

NARA [144]3 years ago

6 0

Okay i will help what’s the question

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Becky, an artist, plans to paint and sell some miniature paintings. She just bought some brushes for $1, and paint and canvas fo

Veronika [31]

Answer:

After one unit is sold, Becky will break-even.

Step-by-step explanation:

Giving the following information:

Fixed costs= $1

Unitary variable cost= $21

Selling price= $22

<u>The break-even point is the number of units required to cover the fixed costs after deducting from the selling price the variable components. At this point, net income is zero</u>.

Break-even point in units= fixed costs/ contribution margin per unit

Break-even point in units= 1 / (22 - 21)

Break-even point in units= 1

After one unit is sold, Becky will break-even.

8 0

3 years ago

Matt claims that 1/3 can indicate a point on a number line as well as distance. Is he correct? Explain.

inna [77]

Yes he is correct because 1/3 can be shown on a number line

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3 years ago

Read 2 more answers

Draw a square with a perimeter of 16 feet

Colt1911 [192]

You need a ruler and a pencil. Oh and paper. Make sure that each side is equal to 4 inches. Then make a scale of 1:12, meaning 1 inch=1 foot.

4 0

3 years ago

I need helpppp with 1-9

BigorU [14]

Hi!! What do you need help with? Solving the problems? Or understanding them? Also 1-9 is a bit blurry, so if you could retake it and repost it, I could solve for them. :). But if you don’t want to, don’t worry.

3 0

3 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago